Shown below is the output from a linear model predicting armspan (in cm) from height (in inches) and summary statistics. Assume that the association between armspan and height is linear. Use the output and summary statistics to complete parts a through d. LinReg y=a+bx a 14.325145628 Mean b 2.272038835 2 = 0.910324833 Height, x 64.14 Armspan, y 160.05 Standard Deviation 3.42 8.15 r 0.954109445 a. Report the regression equation, using the words "Height" and "Armspan," not x and y. A. Predicted Armspan= 14.33 +2.27 Height B. Predicted Height 14.33 +2.27 Armspan C. Predicted Armspan=2.27 +14.33 Height D. Predicted Height = 2.27 +14.33 Armspan Sy b. Determine the corresponding values and verify the slope by using the formula br Sx r= 0.954 (Round to three decimal places as needed.) Sy 8.15 (Round to two decimal places as needed.) Sx3.42 (Round to two decimal places as needed.) b= 2.272 (Round to two decimal places as needed.)

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