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Show that_(csc(x)) = −csc(x) cot(x). dx d (csc(x)) = dx || = dx sin²(x) 1 sin(x) 1 = = -csc(x) cot(x) | ) ‹0) – ¹([ sin²(x) sin(x)

Show that_(csc(x)) = −csc(x) cot(x). dx d (csc(x)) = dx || = dx sin²(x) 1 sin(x) 1 = = -csc(x) cot(x) | ) ‹0) – ¹([ sin²(x) sin(x)

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.5: Derivatives Of Logarithmic Functions
Problem 51E
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Show that__(csc(x)) = −csc(x) cot(x). dx _(csc(x)) dx = = dx sin²(x) 1 sin(x) 1 = −csc(x) cot(x) 1 (0) - 1([ sin²(x) sin(x)
Transcribed Image Text:Show that__(csc(x)) = −csc(x) cot(x). dx _(csc(x)) dx = = dx sin²(x) 1 sin(x) 1 = −csc(x) cot(x) 1 (0) - 1([ sin²(x) sin(x)
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