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Transcribed Image Text:Show that the radial acceleration is zero when 60 =
rad
![Hints: a) The trajectory is given, so to sketch velocity and acceleration vectors at three different points
find the velocity and acceleration (for acceleration a see hints given in part b).
v = ř f + rê ð and a = (* – rở ) î + (rë + 2řė) ôð
The components of velocity and acceleration in polar coordinates should give a feeling about magnitude and direction of vectors
v and a as function of position. You do not need to be perfect in the sketch , just give e feeling (i.e., do not calculate) how the
magnitude and direction of these vectors change as function of position . Remember velocity is always in the tangential direction
with the trajectory, which in our case is a spiral one and not a circular one
from the formula of the acceleration in polar coordinates prove that
5a²f²
b)
a = (* – ri) î + (rë + 2řė) ôð = (¤
2л
2л
5a?f
) ê +
2л
() (1 – 20) F + 50 ê]
a=(
2л](https://content.bartleby.com/qna-images/question/d8694f02-79fe-4b76-9079-b1456b2e1bd2/fb8522c7-d1a9-4179-88f5-a60c52867681/9p2y7kv_processed.png)
Transcribed Image Text:Hints: a) The trajectory is given, so to sketch velocity and acceleration vectors at three different points
find the velocity and acceleration (for acceleration a see hints given in part b).
v = ř f + rê ð and a = (* – rở ) î + (rë + 2řė) ôð
The components of velocity and acceleration in polar coordinates should give a feeling about magnitude and direction of vectors
v and a as function of position. You do not need to be perfect in the sketch , just give e feeling (i.e., do not calculate) how the
magnitude and direction of these vectors change as function of position . Remember velocity is always in the tangential direction
with the trajectory, which in our case is a spiral one and not a circular one
from the formula of the acceleration in polar coordinates prove that
5a²f²
b)
a = (* – ri) î + (rë + 2řė) ôð = (¤
2л
2л
5a?f
) ê +
2л
() (1 – 20) F + 50 ê]
a=(
2л
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