Show that the path of a projectile is a parabola.

Consider a projectile being launched with an initial speed of 43 m/s at a variety of initial angles. Refer to the figure. What is the range, in meters, of the projectile if it is launched at an angle of θ1 = 79.7°?  What is the range, in meters, of the projectile if it is launched at an angle of θ2 = 40.5°?  What is the range, in meters, of the projectile if it is launched at an angle of θ3 = 90 − 79.7°, the complement of θ1?

An airplane flying horizontally at a velocity of 138 m/s and at an altitude of 1500 meters when one of its wheels falls off. a) How long (in seconds) does it take the wheel to reach the ground? b) What horizontal distance (in meters) will the wheel travel before it strikes the ground?

Is this vector addition or subtraction? Then solve: An airplane flies with a velocity of 55.0m/s [35°N of W] with respect to the air (this is known as air speed). If the velocity of the airplane according to an observer on the ground is 40.0m/s [53°N of W], what was the wind velocity?

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle 0 with respect to the horizontal. Let the building be 54.0 m tall, the initial horizontal velocity be 9.10 m/s, and the initial vertical velocity be 10.5 m/s. Choose your coordinates such that the positive y-axis is upward, and the x-axis is to the right, and the origin is at the point where the ball is released. (a) With these choices, find the ball's maximum height above the ground and the time it takes to reach the maximum height. maximum height above ground time to reach maximum height (b) Repeat your calculations choosing the origin at the base of the building. maximum height above ground time to reach maximum height

Use a graphing utility to obtain the path of a projectile launched from the ground (h = 0) at the specified values of θ = 35°, v0 = 300 feet per second. In the exercise, use the graph to determine the maximum height and the time at which the projectile reaches its maximum height. Also use the graph to determine the range of the projectile and the time it hits the ground. Round all answers to the nearest tenth.

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A  projectile is shot from the edge of a cliff with an initial speed of 150 m/s at an angle of 60.0° above the horizon. The cliff is located 125 m above the ground at the bottom of the cliff, which is a flat, featureless horizontal plane that extends as far as the eye can see.(a) Determine the time taken by the projectile to go from the cliff edge to the ground below the cliff. (b) Determine how far horizontally the projectile traveled from the base of the cliff. (c) Determine the velocity vector of the projectile just before it hits the ground at the bottom of the cliff. (d) Include a complete diagram of the situation.

Projectile #1 is launched at t%=DOs at position (0,0) with an initial x-velocity of 5m/s and y-velocity of 10m/s. Projectile #2 is launched 1s after projectile #1 from an initlal position of (1,1) with an x-velocity of 10m/s. Find the following: The position that the 2 projectiles collide at, the time it takes to collide, and the Initial velocity of projectile #2 Including the launch angle.

A projectile is launched at a 350 angle to the horizontal at 24 m/s.  What is the maximum height the object obtains?