Show that a cycle of odd length is an even permutation, and a cycle of even length is an odd permutation. Hence determine which of the following members of S10 are even, or odd: (i) ( 1 9 3) (2 6 ) ( 4 (ii) (1 9 3 2 6) (4 (iii) ( 1 9326 4 5 5 10) (78) 5 10 7 8 ), 10).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 51E
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Show that a cycle of odd length is an even permutation, and a cycle of even length is an odd
permutation. Hence determine which of the following members of S10 are even, or odd:
(i) (1 9 3) (2 6) (4 5 10) (78)
(ii) (1 9 3 2 6 ) (4 5 10 7 8),
(iii) ( 1 9 3 2 6 4 5 10 ).
Transcribed Image Text:Show that a cycle of odd length is an even permutation, and a cycle of even length is an odd permutation. Hence determine which of the following members of S10 are even, or odd: (i) (1 9 3) (2 6) (4 5 10) (78) (ii) (1 9 3 2 6 ) (4 5 10 7 8), (iii) ( 1 9 3 2 6 4 5 10 ).
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