Show me the solution for getting the modulus of elasticity from the initial lope of the curve the answer was 29,000 ksi Sol! -(a) TableS.Alo13५56डो8q101112wad (b)0SSOסט וןoy =1700२२००280033003900[५५००५१००49705025Elongathun xio in -(ablist EX164350700१००13501760२२००2460286038005300780001-753.515393.55 4.519927-3 6-7525362.31 8.829891.30 1135 386.08 12-3०4981.889963-7639855-0714.344334.05419(b) graph is shown(c) E = 2,90x192blpne (from graph)4500 ebline (fromgraph)[45018.11[45516.30/ 3926.5 Sexedsh4000039000YJouan I3250b 2000+15000tonforsof (vided stress) 45dood if inchAx$17AyOF15201911off25(Ex16¹)-(Stain)E (Modules of Elestially) = AyAK30 35 40SStress vs Strain curveSCALE:on xexis-1 spe=5x1= ² (strairOn Y-axis-1 square= 5000 lb/in²4₁+

Modulus of elasticity is defined as the resistance against deformation provided by the material when…

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Civil Engineering

Show me the solution for getting the modulus of elasticity from the initial lope of the curve the answer was 29,000 ksi

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Show me the solution for getting the modulus of elasticity from the initial lope of the curve
the answer was 29,000 ksi

Sol! -
(a) Table
S.Alo
1
3
५
5
6
डो
8
q
10
11
12
wad (b)
0
SSO
סט ון
oy =
1700
२२००
2800
3300
3900
[५५००
५१००
4970
5025
Elongathun xio in -(ablist EX164
350
700
१००
1350
1760
२२००
2460
2860
3800
5300
7800
0
1-75
3.5
15393.55 4.5
19927-3 6-75
25362.31 8.8
29891.30 11
35 386.08 12-3
०
4981.88
9963-76
39855-07
14.3
44334.05419
(b) graph is shown
(c) E = 2,90x192blpne (from graph)
4500 ebline (from
graph)
[45018.11
[45516.30/ 39
26.5

Sexed
sh
40000
39000
Y
Jouan I
3250
b 2000+
15000
ton
fors
of (vided stress) 45dood if inch
Ax
$1
7
Ay
OF
15
20
1911
off
25
(Ex16¹)-
(Stain)
E (Modules of Elestially) = Ay
AK
30 35 40
S
Stress vs Strain curve
SCALE:
on xexis-1 spe=5x1= ² (strair
On Y-axis-1 square= 5000 lb/in²
4₁
+

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