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Show in Figure 1 is the water flow system. The velocity head difference is .  Volume flow rate is .  The heights are  and , respectively.  The power output from the motor is , . The energy added by the pump is . The energy loss between point 1 and 2 is . Calculate  1) power delivered by the fluid to the motor  in kW. ___________kW

Show in Figure 1 is the water flow system. The velocity head difference is .  Volume flow rate is .  The heights are  and , respectively.  The power output from the motor is , . The energy added by the pump is . The energy loss between point 1 and 2 is . Calculate  1) power delivered by the fluid to the motor  in kW. ___________kW

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Show in Figure 1 is the water flow system. The velocity head difference is .  Volume flow rate is .  The heights are  and , respectively.  The power output from the motor is , . The energy added by the pump is . The energy loss between point 1 and 2 is .

Calculate  1) power delivered by the fluid to the motor  in kW. ___________kW

### Water Flow System Overview #### Diagram Description The given diagram displays a water flow system, which includes a motor, a pump, and various points in the system where measurements are taken (labeled as points 1 and 2). The system has the following notable components: - **Motor and Pump:** - The motor drives the pump that moves water through the system. - The pump is situated near the valve where the flow is regulated. - **Piping and Flow Points:** - The piping system includes height changes denoted by \(h1\) and \(h2\). - Heights are specified as \(h1 = 1.0 \, m\) and \(h2 = 2.0 \, m\). #### Known Parameters - **Velocity Head Difference**: \[ \frac{v_1^2 - v_2^2}{2g} = 2.0 \, m \] - **Volume Flow Rate**: \[ Q = 0.5 \, m^3/s \] - **Heights**: \[ h1 = 1.0 \, m, \quad h2 = 2.0 \, m \] - **Motor Power Output**: \[ P_0 = 7.848 \, kW \] - **Motor Efficiency**: \[ e_{M, motor} = 80\% \] - **Energy Added by the Pump**: \[ h_A = 3.0 \, m \] - **Energy Loss Between Points 1 and 2**: \[ h_L = 0.2 \, m \] #### Problem Statement Calculate the power delivered by the fluid to the motor \( P_R \) in \( kW \). ### Solution Steps To solve for the power delivered by the fluid to the motor, we follow these steps: 1. **Convert Motor Efficiency to Decimal:** \[ e_{M, motor} = \frac{80}{100} = 0.8 \] 2. **Find Motor Power Received by the Water:** Using the efficiency formula: \[ P_R = \frac{P_0}{
Transcribed Image Text:### Water Flow System Overview #### Diagram Description The given diagram displays a water flow system, which includes a motor, a pump, and various points in the system where measurements are taken (labeled as points 1 and 2). The system has the following notable components: - **Motor and Pump:** - The motor drives the pump that moves water through the system. - The pump is situated near the valve where the flow is regulated. - **Piping and Flow Points:** - The piping system includes height changes denoted by \(h1\) and \(h2\). - Heights are specified as \(h1 = 1.0 \, m\) and \(h2 = 2.0 \, m\). #### Known Parameters - **Velocity Head Difference**: \[ \frac{v_1^2 - v_2^2}{2g} = 2.0 \, m \] - **Volume Flow Rate**: \[ Q = 0.5 \, m^3/s \] - **Heights**: \[ h1 = 1.0 \, m, \quad h2 = 2.0 \, m \] - **Motor Power Output**: \[ P_0 = 7.848 \, kW \] - **Motor Efficiency**: \[ e_{M, motor} = 80\% \] - **Energy Added by the Pump**: \[ h_A = 3.0 \, m \] - **Energy Loss Between Points 1 and 2**: \[ h_L = 0.2 \, m \] #### Problem Statement Calculate the power delivered by the fluid to the motor \( P_R \) in \( kW \). ### Solution Steps To solve for the power delivered by the fluid to the motor, we follow these steps: 1. **Convert Motor Efficiency to Decimal:** \[ e_{M, motor} = \frac{80}{100} = 0.8 \] 2. **Find Motor Power Received by the Water:** Using the efficiency formula: \[ P_R = \frac{P_0}{
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