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SH)= C -C oct (3) (3) (11 ao Jou. an SI41. coslnutldt K Sode ao と Jode ct こ C (k-0) - IkZ-0)=ck - C.K %3D 2 と rwtlelt scc-ct )coscuwt) dt e と Ses Sudu= cUV - Sv.du C( cos (nwtldt | tcosluw - C.nw cosimwt Ide t C (tosl nwb idyawti c sinluwt) 6k +C Sedsiuln uuk (siuluwk -Siufora.o)| uwk ヒ (K sinluw.lk) -0.Surtuwo)-c (Sinl nw tid (-coslumb)]5 = と = E sınluuks + = {sinluak) + C siwuwk)-S 2c sinluwks + los (ucek) -cos1 = 2c siucuue) +e (wsluwklal) (cosluwklal ) u w 16

SH)= C -C oct (3) (3) (11 ao Jou. an SI41. coslnutldt K Sode ao と Jode ct こ C (k-0) - IkZ-0)=ck - C.K %3D 2 と rwtlelt scc-ct )coscuwt) dt e と Ses Sudu= cUV - Sv.du C( cos (nwtldt | tcosluw - C.nw cosimwt Ide t C (tosl nwb idyawti c sinluwt) 6k +C Sedsiuln uuk (siuluwk -Siufora.o)| uwk ヒ (K sinluw.lk) -0.Surtuwo)-c (Sinl nw tid (-coslumb)]5 = と = E sınluuks + = {sinluak) + C siwuwk)-S 2c sinluwks + los (ucek) -cos1 = 2c siucuue) +e (wsluwklal) (cosluwklal ) u w 16

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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i can't figure out how to determine if a signal is even or odd. can you explain me this example

Setl S4) こ C-c+ octsk (3) A1と ビ 13) (11 ao : Jslaide こ an Jau. 5ifl. cosluutldt ビ So Sce-ce j sodo dt + ao こ ヒ に と cd+ ニ こ ct こ ヒ t」と て IC こ C(ビ-0) -(c2-01- ck- c.K こCk - こ こ 2.7 と こ。 と Sudua C cos (nwtldt こ tcosluw tId6 こUV - Sv.du と C.nw つ cosinwt Ide t c I tcosl nwbldywt こ Lwヒ ヒ ニ c Sinluwt) 6 Sedsiufen uuk ヒ こ C tsing uwt) -s uwk ヒ (ビSinlnw.c) uaに -0. (Sinl nwtidu wt C sincuce こ いw E sinluaks f C siuruwk) (-cosluub)l" = こ in(nwks + cos (ucek)-coS( こ2c sin(nulk + c (cosluwklal) u w 2.
Transcribed Image Text:Setl S4) こ C-c+ octsk (3) A1と ビ 13) (11 ao : Jslaide こ an Jau. 5ifl. cosluutldt ビ So Sce-ce j sodo dt + ao こ ヒ に と cd+ ニ こ ct こ ヒ t」と て IC こ C(ビ-0) -(c2-01- ck- c.K こCk - こ こ 2.7 と こ。 と Sudua C cos (nwtldt こ tcosluw tId6 こUV - Sv.du と C.nw つ cosinwt Ide t c I tcosl nwbldywt こ Lwヒ ヒ ニ c Sinluwt) 6 Sedsiufen uuk ヒ こ C tsing uwt) -s uwk ヒ (ビSinlnw.c) uaに -0. (Sinl nwtidu wt C sincuce こ いw E sinluaks f C siuruwk) (-cosluub)l" = こ in(nwks + cos (ucek)-coS( こ2c sin(nulk + c (cosluwklal) u w 2.
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