Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Please solve these two question detaily and clearly
Transcribed Image Text:unit
4. Setup, but do not evaluate, the integral which would give the area of the region bound by the x-axis
and the curve y = -x² + 6x - 5.
Transcribed Image Text:Use an appropriate substitution to evaluate the integral J
x√5x+2 dx.
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Follow-up Question
Use an appropriate substitution to evaluate the
Please solve correctly detaily
![Use an appropriate substitution to evaluate the integral
\[
\int x \sqrt{5x + 2} \, dx.
\]
### Explanation:
To solve this integral, consider using substitution to simplify the expression inside the square root. Start by letting \( u = 5x + 2 \), then find \( du \) and proceed with integrating in terms of \( u \). This method will simplify the integral, making it easier to evaluate.](https://content.bartleby.com/qna-images/question/0d5d9ef2-562b-49f4-9963-a1c4e47b1118/0fac7e81-6f74-4bb5-8674-4ef1a50cf100/4cjwcah_processed.jpeg)
Transcribed Image Text:Use an appropriate substitution to evaluate the integral
\[
\int x \sqrt{5x + 2} \, dx.
\]
### Explanation:
To solve this integral, consider using substitution to simplify the expression inside the square root. Start by letting \( u = 5x + 2 \), then find \( du \) and proceed with integrating in terms of \( u \). This method will simplify the integral, making it easier to evaluate.
Solution
by Bartleby Expert
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question
Use an appropriate substitution to evaluate the
Please solve correctly detaily
Transcribed Image Text:Use an appropriate substitution to evaluate the integral
\[
\int x \sqrt{5x + 2} \, dx.
\]
### Explanation:
To solve this integral, consider using substitution to simplify the expression inside the square root. Start by letting \( u = 5x + 2 \), then find \( du \) and proceed with integrating in terms of \( u \). This method will simplify the integral, making it easier to evaluate.
Solution
by Bartleby Expert
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