SELECT P.NAME, P. EMAIL FROM PASSENGER P WHERE P.ID NOT IN SELECT PASSENGER_ID FROM RIDE_PASSENGER;
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- SELECT FIRST_NAME, LAST_NAME, SCHOOL_FEE FROM STUDENT, FEE_PAYMENT WHERE STUDENT. STUDENT_ID=FEE_PAYMENT. STUDENT_ID ORDER BY FIRST_NAMEMy resualt has error? SELECT last_name,customer_number2 from CUSTOMERS WHERE REFERRED is not null;SELECT last_name,customer_number*ERROR at line 1:ORA-00904: "CUSTOMER_NUMBER": invalid identifier List all customers who were referred to the bookstore by another customer. List eachcustomer’s last name and the number of the customer who made the referral.53. Which SELECT statement retrieves the customer name for those that have a salesperson number of 137? A: SELECT CUSTNAME FROM CUSTOMER WHERE SPNUM 137; B: SELECT* FROM CUSTNAME WHERE SPNUM=137; C: SELECT CUSTOMER FROM CUSTNAME WHERE SPNUM=137; D:SELECT* FROM CUSTOMER WHERE SPNUM=137
- the employee table have the following . ask user what is the employee_id and how much employee wants to contribute 2 substitutions variable from end user &emp_id &contribution_amount If employee salary is in between $1000-$3999 And if employee's contribution amount is less than $100 then company match $100 if employee's contribution amount is greater than 100 but less than $200 then company match $75 if employee's contribution amount is greater than $200 then company match $50 $4000-$6999 And if employee's contribution amount is less than $100 then company match $150 if employee's contribution amount is greater than 100 but less than $200 then company match $100 if employee's contribution amount is greater than $200 then company match $75 $7000-$12000And if employee's contribution amount is less than $100 then company match $200 if employee's contribution amount is greater than…Display the customer ID, name, and order ID for all customer orders. For those customers who do not have any orders, include them in the display once by showing order ID 0.The command DESC DEPARTMENTS shows the following information Name Null? Туре DEPARTMENT_ID NOT NULL NUMBER (4) DEPARTMENT NAME NOT NULL VARCHAR2 (30) MANAGER ID NUMBER (6) LOCATION_ID NUMBER (4) Which of the following is correct This table has a primary key. This table has a foreign key. This table has both primary and foreign keys. This table has neither primary nor foreign keys. Not enough information to answer. 10 points
- Display the customer ID, name, and order ID for all customer orders. For those customers who do not have any orders, include them in the display once.31 Refer to the given SQL statement. SELECT PRODNUM, PRODNAME FROM PRODUCT: Which line designates a product number of at least 300 when added to the end of this statement? O WHERE PRODNUM>=300 WHERE PRODNUM=300+ O WHERE PRODNUM=(300; unlimited) WHERE PRODNUM=>300Choose the SELECT statement that returns the given results from the Auto table below. ID Make Model Type Year Price 1 Toyota Camry sedan 2016 9800 2 Ford Escape crossover 2015 15900 3 Honda Civic sedan 2016 10200 4 Volkswagen Golf compact 2014 8800 5 Toyota RAV4 crossover 2016 12800 6 Toyota 4Runner suv 2015 16900 7 Honda CR-V crossover 2016 17900 Result : Honda 2 Toyota 3 Select Make, Count(Make) FROM Auto Group By Make; Select Make, COUNT(Make) From Auto Group By Make Having Count(Make) > 1; Select Make, Count(Make) From Auto Group By Make Having COUNT >1;
- How many days, years did quitting employees work in their past jobs. Name Null? Туре ΕMPLOYEE_ID FIRST_NAME LAST_NAME NUMBER (6) VARCHAR2 (20) NOT NULL VARCHAR2 (25) ΕΜΑIL NOT NULL VARCHAR2 (25) PHONE_NUMBER VARCHAR2 (20) NOT NULL DATE HIRE_DATE JOB_ID NOT NULL VARCHAR2 (10) NUMBER (8,2) NUMBER (2,2) SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID NUMBER (6) NUMBER (4) Name Null? Туре NOT NULL NUMBER (6) ΕMPLOYEE_ID START_DATE END_DATE JOB_ID DEPARTMENT_ID NOT NULL DATE NOT NULL DATE NOT NULL VARCHAR2 (10) NUMBER (4)r and l values question.Display the customer names of all customers who have ordered (on the same or different orders) both products with IDs 3 and 4.