sec?xsec'y dx dy .2

Q: ye(2y*) dy

A: Given the integral I=∫ye2y2dy     ....(1)

Q: find dy / dx by implicit differentiation.

A: In implicit differentiation, on differentiating y, we use dy/dx.

Q: Differentiate. y = Jex +8 dy dx

A: The given equation is y=ex+8 To find: dydx

Q: aluate 4e3 tan z sec2 x dx.

A:

Q: COs x dy Find when y = dx csc(7x + 1)' dy dx

A: The given function is y=cosxcsc(7x+1)

Q: find dy/dx, y=tanx-secx

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Q: Solve dy dx cos x = cos x cst ² y

A: A differential equation can be solved using the variable separation method. In this method, the…

Q: 1. (4 - y?)dy dx

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: dy Find where y = sin²(V3x²). dx

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Q: Integrate: Stan? (3x) secº (3æ)dx ес

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Q: Solve 3e* tan y dx+(1-e*)sec² y dy = 0.

A: To solve the given differenrial equation.

Q: sin y dy dx

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Q: dy when x = 0, dx Find

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Q: cos y` +y = tanck) %3D

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Q: Solve dy dx + y tan x = -y³x sec²(x)

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Q: tan y dy + In (secy) In (6)sec® de

A: Given data:     The given integral is: . The given integral can be written as, Assume Let…

Q: sin(y)dx + cos(y)dy = 0 by exact

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Q: 2e*/y dy dx 2.

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Q: 3 4-y y dx dy = 1 2y MIN

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Q: dy = sin(x+4) dx

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Q: dy + (secx)у 3 dx 10 secx + taпх

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Q: Find dy/dx if y = sec^3(1/x)

A: Given:

Q: Which differentiation rule is used to show d/ dx sin y = cosy dy/dx ?

A: To Determine: Which differentiation rule is used to show d/ dx sin y = cosy dy/dx ? Given: we have…

Q: & dy +16y=-Si Sinx

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Q: arctanx e dx (1+x²,"

A: The given problem is to evaluate the given integral. We have to evaluate by using substitution…

Q: sech? dx 1- sech Vĩ tanh Vi dt Vi 2-

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Q: sinx So Sa* y dy dx fi dx dy 3. 4-

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Q: Solve this DE 1. dy/dx+secx(y-2sec3x+2sec2 xtanx) + y cotx = 0

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Q: solve sin2x dy/dx-y=tan x

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Q: dx wherein x(2) = 4 り dy

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Q: Find dy/dx in terms of x and y if arctan (x^3)=xy^3?

A: To find the derivative of the given function.

Q: I3Jsin'x cos x dx .6,

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Q: Find when y = cos(sin 2x). ay dx dy dx

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Q: (3 sin y – 5x)dx + 2x2 cot y dy = 0 -

A: Solution :-

Q: sin(y*) dy dx

A: the limit of x is  the limit of y is

Q: Evaluate dy/dx if y = (sec2x - tan2x)/(2cos2x-1)

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Q: (3 sin y – 5x)dx + 2x² cot ydy = 0

A: Given the differential equation:       (3sin y-5x)dx+2x2cot y dy=0 Solve using substitution method.

Q: solve sin2x dy -y=tanx dx

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Q: find dy/dx,y= cotx-tanx

A: Given function is Derivative of cotx is -(cscx)^2 and derivative of tanx is (secx)^2 Therefore,

Q: dy/ dx sinx=y cosx +sin²x

A: see 2nd step

Q: 1 tanx dy dx Ja 1+ y2 а

A:

Q: | sec? (y) /2+ tan(y) dy V

A: To evaluate: ∫0π sec2y 2+tan ydy

Q: |tanx dx = -In/secx|+C A In/secx + C B In/cscx +C .C -In/cscx +C D

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Q: calculate the derivative.

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Q: Cosx 2) ). y dx+ týž - Sinx (²) dy = уч

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Q: What is dy/dx of the function y=tanh(sec x)?

A: To find the differentiation of the given function.  y = tanh(Sec(x)).

Q: dy Find where y = sec-' (V3x³). dx

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Q: 9. 2y(у? — х)dy — dx, when x %3D2,у %3D 2

A: Given that: 9.     2y(y2-x)dy=dx,    when x=2, y=2     NOTE: As per our answering guidelines, we can…