Need help on this asap. Pls. Thanks a lot. PROBLEM 4A 13-meter-span simply supported is made of a WF section which islateraly supported at 2 meters from the left support.Prop. of WF sectionA = 9100 mm?d = 523 mmbf =207 mmrx = 209 mmly = 16.1 x 106 mm4 mm6Sy = 156 000 mm3ry = 42.2 mmJ = 0.334 x 10^6 mm^4Zx = 1750 000 mm3W = 72 kg/mFy %3D 345 MPаtf = 10.90 mmtw =8.89 mmCb = 1.14Ix = 399 x 10^6 mm^4Sx = 1520 000 mm^3Cw = 1060 x 10^12 mm^6%3DUsing ASD, compute the allowable moment of the beam.b.а.Using LRFD, compute the design strength of the beam.Compute the uniform service live load it can carry if the uniformdead load (excluding self weight) is 20 kN/mС.

work out admissible development of the beam according to ASDallowable movement MB=Fy×Sx…

Answered: section rx = 209 mm ly = 16.1 x 106 m…

Engineering

Civil Engineering

section rx = 209 mm ly = 16.1 x 106 m Sy = 156 000 mr mm?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Determine the design moment capacity of the beam with given properties below. bf = 550mm bw = 350mm tf = 110mm d = 370mm %3D d' = 100mm fc' %3D 34.5 MРа fy = 400 MPa As = 6 - 28mm bars %3D USE NSCP 2015, Mu = kN-m %3D
Fobe Acrobat Reader DC indow Help exercisechapter3.pdf x 2 /2 135% 4. Determine the vertical displacement of joint Cof the truss. Each member has a cross-sectional area of Use the method of virtual work. Given E = 200 GPa. A 300 %3D mm2. H. 3 m E- B 4 m -4 m 4 m - 4 m 3 kN 3 kN 4 kN (Answer: 4.91 mm
Y. 3.5 314 1. The cross section shown in the figure is a structural member known as a z- section.Compute the following: (1) cross sectional area, (2) centroidal moment of inertia,lxo. And (3) centroidal moment of inertia, Iyo. 2.625 6-4.5 -X, -3/4 314] 3/4 '1.375 3.5
SITUATION II I. Refer to Figure SSE - 0001. The combination section shown consists of a wide flange and a channel. Properties of section are: W 66 х 125 A = 19548 mm² d = 612.1 mm tw = 11.9 mm bf = 229.1 mm tf = 19.6 mm Ix = 986, 468 x 10’ mm' Sx = 3223.2 x 10’mm³ rx = 248.8 mm Iy = 39,292 x 10' mm Sy = 343 x 10' mm³ ry = 49.66 The beam is subjected to a uniformly distributed load (KN/m) weight included of 30 KN/m throughout the simply supported span of 6m and a moving load P (KN). с 300 х З1 A = 3929 mm² d = 304.8 mm tw = 7.2 mm bf = 79.7 mm tf = 12.7 mm x = 17.73 mm Ix = 53694 x 10³ Sx = 352.3 x 10’mm rx = 116.9 mm Iy = 1615 x 10’ mm° Sy = 28.7x 10’ mm mm FIGURE SSE - 0001 ry = 20.27 4. Calculate of resisting combination section if the allowable flexural strength, the moment (KN-m) the Fb = 165 MPa. A. 445 В. 430 C. 569 D. 587 5. Calculate the load P (KN) of the combination section if the allowable flexural strength, Fb = 165 MPa is not exceeded. A. 204 В. 142 C. 165 D. 304 6. If the…
Determine the true length of lines SD and PF. Then draw the point view of line SD. Use only two additional views. Note: Properly label your ARP's, TL's, and PV's. SD = HRP FRP S S mm F₁ Pl PF = + D PF (PV) D mm
Find the Beam Design Moment Strength. 250 So - 19.5 30 -75- 20 100 100 50 50 46 -40 31.15.7 29.8 180 3 Seven wire strand A = 99mm² x 3 f'c = 55M²₂² ty = 400MPa 2 201 Steel d=18.5mm A=300mm² for each 500mm Ecu=0.003
Compute the vertical distance of link AB from pin E for the given set up if the tension in link AB is equal to 1500 lb and the ratio of di to d2 is 7:8. -32"- E 12" C D A В d2 800 lb LLLLL LLLL G F 28" swer: d; = 21", total distance from pin E = 33"
3. Determine the moment of inertia with respected to 25 mm x- (horizontal) and y- (vertical) axis through the centroid of the two 250 x 25 mm steel plates and two C381 x 74 channels that are welded together 254 mm C381 x74 to form the cross section shown in Figure 3. 25 mm 250 mm- Axis XX Axis YY Flange Thicknesu Wob Thickness Arca mm2 Depth Wid th 108 mmt Shape C381 x 71 105 mmt 1.58 mm mm mm mm mm mm 9485 381 91.4 165 18.2 168 133 22.0 20.3
AW 24 x 103 is used as a beam that is simply supported at its ends. The properties of the section is as follows: Ix = 1,248,694,000,000 mm4 Sx = 4,008,005 mm3 rx = 252.74 mm ly = 49,532,000,000 mm4 Sy = 433,350.83 mm4 ry = 50.34 mm d= 623.10 mm tw = 14.00 mm bf = 228.60 mm tf = 24.90 mm A = 19,548.00 mm2 W = 153.76 kg/m rt = 59.18 mm The beam is laterally supported at supports only. Use Fy = 248 MPa. a) Determine the allowable bending stress for a length of 2 m. b) Determine the allowable bending stress for a length of 4 m. c) Determine the allowable bending stress for a length of 9 m.
1:01 < 21_S_5_TrussDeflection... Q Structural Analysis СЕ З32 Classwork Find the vertical deflection at joint C under the loading shown. The area of all bars are the same and equal to 4 in' and E- 30,000 ksi. A is a pin and B is a roller support. 40 30 30 Figure P-3 25 Dashboard Calendar To Do Notifications Inbox
4: AW section is used as a beam without lateral support. A-36 steel is used. Properties of W- Section: A= 24709.6 mm d 840.74 mm bf 292.35 mm tf = 21.72 mm tw = 14.73 mm 1=2792.9 x 10 mm 1, = 90.74 x 10 mm S, = 6653.15 x 10 mm S, = 621.07 x 10 mm r,= 335.28 mm r 60.45 mm %3D a. Compute the allowable bending stress if it has a simple span of 3.5m b. Compute the allowable bending stress if it has a simple span of 4m. C. Compute the allowable bending stress if it has a simple span of 7m. d. Compute the allowable bending stress if it has a simple span of 9m.
2 kip/fn 40 kip-ft 10 ft 10 ft The simply-supported beam above is made of a steel wide-flange section with the following properties: • E = 29000 ksi •G = 10000 ksi A = 12.6 in? | = 428 in4 Which of the following is closest to the slope/angle of the beam at point A? +0.00721 rad -0.00928 rad +0.0213 rad -0.0160 rad