
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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f) The iris of the eye serves two different purposes. First, the iris controls the total amount of light entering the eye so a person can see in varying light levels. Secondly, the iris blocks light from hitting the extreme edges of the crystalline lens. Why might an eye want to block the light hitting the extreme edges of a lens? What is the name for the effect when light does hit the edges of a lens? Can you understand why a person’s vision is blurred when they get their eyes dilated at the doctor?
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- 1. Consider a cuboid made of crown glass which has inner space filled with water. A ray of light is incident onto the 10 cm thick block of glass on the top face of the cuboid at 60◦ from the normal. It then meets the glass-water boundary and is refracted again and continues through a water thickness of 5 cm before reaching another water-glass boundary. The ray of light is again refracted and continues in the 10 cm thick block of glass on the base of the cuboid and eventually exits into air. (a) Draw a clearly labelled diagram of the path the ray of light takes. (b) Calculate all the angles of refraction and incidence at each boundary. (c) Calculate the optical path of the ray of light from the point it is incident on the surface of the cuboid to the point it exits into air on the other end.arrow_forwardA 45°-90°-45° prism is constructed from a synthetic resin. As shown in the figure, a light beam that enters the prism at the midpoint of the long side and parallel to the base exits the prism at an angle of 33° below the horizontal. What is the index of refraction of this prism? Additional Materialsarrow_forwardCreate a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.arrow_forward
- A1. As shown in Figure A1, a light ray is incident normal to one face of a 30°-60°-90° prism (n = 1.50) that is immersed in water (n = 1.33). Determine the exit angle 03. (a) Determine the exit angle 03. (b) Determine the critical angle for the prism-water system. n2 60.0° n1 Figure Al 021 30.0% D 103arrow_forwardSome lenses are shaped with one flat side and one spherically-shaped side. This shape is designed to focus parallel light rays onto a single point. In a few sentences, explain how the spherical shape of the lens' surfaces causes parallel light rays to focus on a single point. (Assume the light is travelling through air into a lens with an index of refraction greater than that of air.) Focal length Focal pointarrow_forward2. In the image below, an incident ray shines at an angle onto two layers of class. The first layer has an index of refraction of 1.47. The second layer is of an unknown index. You have determined the point at which the ray exits the second layer of glass. You will need a protractor to measure angles in this problem. (A) Determine the angle of refraction of the ray inside the first material. (B) Trace the path of the ray through the first and second layers of materials on the picture below. (C) Determine the unknown index of refraction in the second material. (D) Determine direction of and draw the path of the ray after it exits the second layer. point where ray exits second layer. air n2 = ? ni = 1.47 air incident rayarrow_forward
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