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sec2X - 4secX = 0 [ 0, 2pi )
I do not understand why one of the solutions is
-arcos(1/4)
Why is it negative? If positive
2pi - acros(1/4)
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Trigonometry (Mind Tap Course List ISBN: 9781337278461 10th Edition
Sec. 2.3 Prob # 68E
The explanation in Bartleby and in the textbook for the given problem is..
Solution: - arccos (-1/4) + (2pi) (n) ....along with other solutions...
My question: Would I be incorrect for substituting this solution with the following:
Solution: 2pi - acros(1/4) + (2pi) (n)
Trigonometry (Mind Tap Course List ISBN: 9781337278461 10th Edition
Sec. 2.3 Prob # 68E
The explanation in Bartleby and in the textbook for the given problem is..
Solution: - arccos (-1/4) + (2pi) (n) ....along with other solutions...
My question: Would I be incorrect for substituting this solution with the following:
Solution: 2pi - acros(1/4) + (2pi) (n)
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