scallop-shaped wings and 67 have normal wings. Results were similar for reciprocal crosses. have normal wings. If they cross flies with scalloped-shaped wings, 133 of the offspring have true breeding wildtype flies with normal wings, 87 of the offspring have scalloped wings and 90 I. When researchers naped wings with What are the observed phenotypic ratios for these two crosses?

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Drew
1. When researchers cross fruit flies (Drosophila melanogaster) with scalloped-shaped wings with
true breeding wildtype flies with normal wings, 87 of the offspring have scalloped wings and 90
have normal wings. If they cross flies with scalloped-shaped wings, 133 of the offspring have
scallop-shaped wings and 67 have normal wings. Results were similar for reciprocal crosses.
What are the observed phenotypic ratios for these two crosses?
b Use the table below to perform a x' test on the cross between two flies with scalloped wings
to compare your observed counts to the 3:1 ratio expected for a cross between to
heterozygotes with complete dominance. Round your final x to 2 decimal places
(0 - E)
E
Observed
Expected
Phenotype
Counts
Counts
(0 - E)
(0-E)
Scalloped wing
133
Normal wing
67
Total
200
Degrees of freedom:
P value:
c. Write a descriptive sentence summarizing your results, as described in lecture.
C. Based on the observed ratios in (a) and vour y2 test in (b), describe a biological hypothesis
that explains these results, Draw Punnett squares to support your hypothesis. Use sa for
uie hormal allele and sd for the sealloped allele. E.g. a true breeding wildtype fly is sd+sd+.
Transcribed Image Text:Drew 1. When researchers cross fruit flies (Drosophila melanogaster) with scalloped-shaped wings with true breeding wildtype flies with normal wings, 87 of the offspring have scalloped wings and 90 have normal wings. If they cross flies with scalloped-shaped wings, 133 of the offspring have scallop-shaped wings and 67 have normal wings. Results were similar for reciprocal crosses. What are the observed phenotypic ratios for these two crosses? b Use the table below to perform a x' test on the cross between two flies with scalloped wings to compare your observed counts to the 3:1 ratio expected for a cross between to heterozygotes with complete dominance. Round your final x to 2 decimal places (0 - E) E Observed Expected Phenotype Counts Counts (0 - E) (0-E) Scalloped wing 133 Normal wing 67 Total 200 Degrees of freedom: P value: c. Write a descriptive sentence summarizing your results, as described in lecture. C. Based on the observed ratios in (a) and vour y2 test in (b), describe a biological hypothesis that explains these results, Draw Punnett squares to support your hypothesis. Use sa for uie hormal allele and sd for the sealloped allele. E.g. a true breeding wildtype fly is sd+sd+.
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