Say you have 1.50 M M9SO, solution and you need 200. mL of 0.600 M MgSO. How can you prepare this dilution?* Take 40 mL of a 1.50 M solution and pour into a flask. Add water until total volume equals 100 mL. Take 80 mL of a 1.50 M solution and pour into a flask. Add water until total volume equals 200 mL. Take 40 mL of a 1.50 M solution and pour into a flask. Add water until total volume equals 200 mL. Take 500 ml of a 1.50 M solution and pour into a flask. Add water until total volume equals 200 mL.

Determine the initial volume (in mL) needed to generate each of the following desired solutions by dilution. a. 12.0 L of 0.75 M solution from 2.5 M solution Volume = mL b. 3.93 L of 2.65 M solution from 11.6 M solution Volume = mL c. 100.0 mL of 0.060 M solution from 1.95 M solution Volume= mL d. 57.0 mL of 4.4 x 10-4 M solution from 0.15 M solution mL Volume =

In the laboratory you dilute 4.49 mL of a concentrated 6.00 M nitric acid solution to a total volume of 100 mL. What is the concentration of the dilute solution?

You are asked to create a 0.35 M solution of calcium chloride (CaCl2) using a 250.0 mL volumetric flask. Calculate the mass of CaCl2 needed to make this stock (original) 0.35 M CaCl2 solution.   You are asked to create 50.0 mL of 0.15 M CaCl2 from the stock solution you made in (A). Calculate the volume of stock solution you need to create your diluted solution.   You have two solvents, difluoromethane (CH2F2) and ethanol (C2H5OH) available to dissolve your CaCl2. Which solvent would be more appropriate to use? Justify your response in 2 sentences or less.   You react 30.0 mL of  0.35 M CaCl2 with excess solid lithium. The balanced reaction is shown below. What mass of solid calcium is made during this experiment? CaCl2(aq) +  2 Li(s) → Ca(s) + 2 LiCl(aq)

If 52.00 ml of 0.500 M CaBr 2 solution is added to  128 ml of 0.320 M solution of KCl solution, what  will the molarity of CaBr 2 and the molarity of KCl in the final solution? (assume  volumes are additive)

A student is preparing 0.5 L of a 0.1 M magnesium chloride solution. The student uses the following steps to get started.            Step 1: Gather a graduated cylinder, balance, and stirring rod.      Step 2: Calculate the number of moles of magnesium chloride needed.      Step 3: Add enough water to reach the 0.5 L mark of magnesium chloride solution and stir until dissolved.      Step 4: Label the solution 0.1 M MgCl2.  The process as described is incomplete. What would fix the process so that it is accurate?   A The student made a mistake in Step 1 by getting a graduated cylinder. The student should have gotten a beaker. B The student made a mistake in Step 2 by only calculating the moles of magnesium chloride. The grams should also be calculated to make the solution.  C The student made a mistake in Step 3 by adding enough water to reach 0.5 L mark of solution. Exactly 0.5 L of water should have been added. D The student make…

equals 300 ml. How would you prepare 275 mL of 0.600M K,PO, solution? * O I would add 35.0 g K,PO, to enough water to make 275 mL of solution. O I would add 25.0 g K,PO., to enough water to make 275 mL of solution. O I would add 0.165 g K,P0, to enough water to make 275 mL of solution. O none of these is correct Water and alcohol are twO liquids. *

7. Using a 6.2 M solution of MgSO; determine how to make 240 mL of a 1.3 M dilution.

How many mL of water should be added to 50.0 mL of a 15.0 M H2SO4 solution to give a final concentration of 0.300 M? A) 950 mL B) 1000 mL C) 2450 mL D) 2500 mL

Say you have 2.50 M Caso, solution and you need 300. mL of 0.400 M CaSO, How can you prepare this dilution? * Take 32 mL of a 2.50 M solution and pour into a flask. Add water until total volume equals 200 ml. Take 48 mL of a 2.50 M solution and pour into a flask. Add water until total volume equals 300 ml. Take 1875 mL of a 2.50 M solution and pour into a flask. Add water until total volume equals 300 ml. Take 120 mL of a 2.50 M solution and pour into a flask. Add water until total volume equals 300 ml. How would you prepare 275 mL of 0.600 M KPO, solution? * Twould add 35.0 g K.PO, to enough water to make 275 ml of solution