Saturated vapor water at 100 kPa enters an isentropic compressor and exits at 2 MPa. Note that isentropic implies adiabatic and reversible. a) What is the temperature of the outlet in \deg C. Round to one decimal place. b) How much work, in kJ/kg, must be used for this process? Round your answer to one decimal place. Hint: Don't use temperature to perform the interpolation!

Saturated vapor water at 100 kPa enters an isentropic compressor and exits at 2 MPa. Note that isentropic implies adiabatic and reversible. a) What is the temperature of the outlet in \deg C. Round to one decimal place. b) How much work, in kJ/kg, must be used for this process? Round your answer to one decimal place. Hint: Don't use temperature to perform the interpolation!

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter2: Matter And Energy

Section: Chapter Questions

Problem 29RQ: If 3000 ft3 of air is crossing an evaporator coil and iscooled from 75F to 55F, what would be the...

See similar textbooks

Similar questions

02 A- Find internal energy and enthalpy of superheated steam at 100 bar and degree of superheating of 110 °C?
Correct and Fast Please
Please answer f,g,h, and i as well. I need this now. I posted this as separate but was answered same as the other one.Thank you.f) actual entropy at steam outlet. g) Actual temp. of steam at the exhaust. h) irreversible adiabatic expansion efficiency. i) ∆S for irreversible adiabatic process
Hi please help me understand and answer this question with clear units thank you very much
Solve and include units in the process. Clue for A. 2.31kg/min B? C?
Complete solution with cancellation of units please. Thank you!
QUESTION 56 A fluid at 0.8 bar occupying 0.09 m² is compressed reversibly to a pressure of 10 1 bar and specific volume of 0.7 m/kg according to the law pv = c. The fluid then expands reversibly according to the law pvZ= c to 2 9 bar Areversible cooling at constant volume then restores the fluid back to initial state. Calculate the net work for the process in Joules to round figure No mega or Kilo for units.
Q1: Mass flow through a sonic nozzle is a function of gas pressure and temperature (Pressure = P, Temperature = T). If the mass flow rate through the nozzle is given by: m = 0.0430 70.5 Where: m Ib/min, P = Psia, T = °R a) Determine what the units for the constant 0.0430 are? b) What will be the new value of the constant, now gives as 0.0430, if the variables in the equation are to be substituted with SI units and m is calculated in SI units? Q2: Some of fermentation organism which is used to analyze the waste water from oil refinery can live at reduced air pressure down to 22 Kpa. In a test a mercury manometer attached to a tank reads 64.5 cmHg and the barometer reads 104 Kpa. Will the organize live at this conditions?
solve a,b, c and d please. In a detergent-making process, 1400gal/h of water ﬂows through a 2-inch pipe system as follows: Exit from pump, 2ft vertical, open gate valve, 14 ft vertical, 908 bend, 12ft horizontal, 1/4 open globe valve, 20ft horizontal, 908 bend, 6ft horizontal, 908 bend, 12ft vertical, 908 bend, 14ft horizontal, 908 bend, 4 ft vertical, 908 bend, 28ft horizontal, open gate valve, 3ft horizontal, entry to tank containing 30ft of liquid. (a). If the pump and tank are both at grade level, estimate the head that the pump must deliver. (b). If the pump inlet pressure is 25 psig, what is the outlet pressure? (c). Estimate the pump shaft work ( d). If the pump is powered by an electric motor with 85% efﬁciency, what is the annual electricity consumption?
Don't use chatgpt,I need the correct solution. Answer is provided .
If 3000 ft3 of air is crossing an evaporator coil and iscooled from 75F to 55F, what would be the volume of air, in ft3, exiting the evaporator coil?
The motion of a liquid in an open tank is that of a combined vortex consisting of a forced vortex for 0 2 ft. The velocity profile and the corresponding shape of the free surface are shown in Fig. 6 . The free surface at the cen- ter of the tank is a depth h below the free surface at r = o. Deter- mine the value of h. Note that h = hforced + h&ce Where hforced and hfee are the corresponding depths for the forced vortex and the free vortex, respectively. 8-