samples are independe study was body tempera random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. State th conclusion for the test. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. μ n FIX X S Men H1 11 97.66°F 0.75°F Women H₂ 59 97.22°F 0.68°F O A. Reject the null hypothesis. There is not sufficient evidence to support the claim that men have a higher mean body temperature than women. O B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that men have a higher mean body temperature than women. O C. Reject the null hypothesis. There is sufficient evidence to support the claim that men have a higher mean body temperature than women. O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that men have a higher mean body temperature than women.

The mean score on EDA prelim exam is 60, with a standard deviation of 5.2. Between which two scores must this mean lie to represent at least 75% of the data set? Ans is Blank 1 Blank 1 Add your answer

At a college, the mean height of women is 64 inches with the standard deviation of 5 inches. What is the z-score for a height of 59? What is the z-score for a height of 74? What is the height of a woman with a z-score of 3? Submit Question

A survey found that the average hotel room rates and standard deviations for the state of Arkansas and the state of Washington. Assume that the data were obtained from two samples were normally distributed. At a=0.1 level of significance, can it be concluded that there is a significant difference in the rates? Use the data table below. Report only the value required from the question below make sure to express your final answers in 4 decimal places. Parameter Arkansas Washington Sample size 82.00 72.00 sample 350.46 360.01 mean population standard deviation 29.17 27.20 a. Variance of Arkansas:

Calculate the sample standard deviation- question at the bottom. I solved everything else on my own.

find the mean and standard deviation for A B C Sample a: 12. 21.30 Sample b: 70, 79,88 Sample c:1,045, 1,054, 1063 also what does this exercise show about the standard deviation?

Answer using MS Excel. A certain machine produces components having a mean length of 15 centimeters. As a result of measuring samples of these components, it is found that the standard deviation is 0.2 centimeters. A test is carried out and it is found that the lengths of the components are normally distributed. Determine the number of components likely to have a length of less than 14.95 cm in a batch of 10,000 components. Determine the number of components likely to be between 14.95 cm and 15.15 cm in a batch of 10,000 components. Determine the number of components likely to be greater than 15.43 cm in a batch of 10,000 components.

T-TEST FOR ONE SAMPLE MEAN A DepEd official claim that the average performance in Mathematics is 82.4%. A random of 25 students showed that their mean performance in Mathematics is 81.3% with a standard deviation of 4.2%. Test whether the mean performance of the students is not significantly lower than the general average. Use 0.01 level of significance.

i already have answer in question A-C. please help me answer the rest. topic unknown standard variation thank you