### Five-Number Summary and Interquartile RangeHere are yesterday's high temperatures (in Fahrenheit) in 13 U.S. cities:48, 52, 54, 56, 57, 59, 63, 66, 72, 78, 78, 81, 82Notice that the temperatures are ordered from least to greatest.**Objective:**Give the five-number summary and the interquartile range for the data set.**Five-Number Summary:**| | ||-----------|-------------|| Minimum: | [Value] || Lower Quartile: | [Value] || Median: | [Value] || Upper Quartile: | [Value] || Maximum: | [Value] || Interquartile Range: | [Value] |**Instructions:**1. **Minimum**: The smallest value in the data set.2. **Lower Quartile (Q1)**: The median of the lower half of the data set.3. **Median**: The middle value of the data set.4. **Upper Quartile (Q3)**: The median of the upper half of the data set.5. **Maximum**: The largest value in the data set.6. **Interquartile Range (IQR)**: The difference between the upper quartile and the lower quartile (IQR = Q3 - Q1).By filling in the correct values, you will complete the five-number summary and determine the interquartile range. Click the "Check" button to verify your answers. For assistance, click "Explanation".

Given data: 48, 52, 54, 56, 57, 59, 63, 66, 72, 78, 78, 81, 82. The sample size is n=13.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F98.6∘F. You collected data using 36 healthy people and found that they had a mean body temperature of 98.21∘F98.21∘F with a standard deviaiton of 1.18∘F1.18∘F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6∘F98.6∘F.a) Identify the null and alternative hypotheses?H0H0: ? p = p ≠ p < p > p ≤ p ≥ μ = μ ≠ μ < μ > μ ≤ μ ≥ H1H1: ? p = p ≠ p < p > p ≤ p ≥ μ = μ ≠ μ < μ > μ ≤ μ ≥ b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? left-tailed right-tailed two-tailed c) Identify the appropriate significance level.d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.e) Calculate your p-value. Write the result below, and be sure to round your final answer…
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Home-myRCC mylearning.suny.edu/d21/le/content/920969/viewContent/25846458/View The following data represents the age of 30 lottery winners. Given the frequency distribution for the data, Age Frequency Relative Frequency Cumulative Relative Frequency [20,29] 0.1667 [30,39] 0.1 [40,49] 0.2 [50,59] 0.1 [60,69] [70,79] [80,89] 8 ✓ A.1 HW-23FA STATISTICS (81 x 5 3 6 3 4 8 1 What is the frequency of lottery winners of age between 19 and 40? 30 ✓% 0.1333 0.2667 0.0333 What percentage of lottery winners are 70 years or older? 0.266 + What is the relative frequency of ages under 40? What is the cumulative relative frequency of lottery winners younger than 50? O 0.1667 0.2667 0.4667 0.5667 0.7 0.9667 1 SEP 13
175% O ALTITUDES (OH MYI (ОН МУН en information to find each value. 2. Find x and RT if SU is a median of ARST. on TU UR def of 2x+24 2x +24=5x-30D medion 5x-30 X =18 X-18 RT=120
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kindly recheck this because I posted it on my other account but I think the first answer is wrong, I trust you to recheck it properly.

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