Homework Help is Here – Start Your Trial Now!
Math
Probability
s tan dard deviation(a) = 348 s tan dard deviation(o) = 112 Required probability is P x< 650 Required probability is P( X > 100 -() = P 650–p 100- = P( 650-789 100-70 Z > 348 112 = P(Z < -2. 08) = P(Z > 1.34) from Z-table = 0. 0901 from Z– table = 0.0188 The probability that the mean price is less than 650 is 0.0188. b) Given, sample size(n) = 42 mean(u) = 10 s tan dard deviation(6) = 13 Required probability is P < 15 = P -- ) - r(2- = P 10 < Z < 15- 15-10 = P(-0. 50 < Z < 2. 49) -0. 50 = 0. 9936 – 0. 3085 (from Z – table = 0. 6851 The probability that the mean no.of hours a week spent playing video games is between 9 and 15 is 0. 6851. II

s tan dard deviation(a) = 348 s tan dard deviation(o) = 112 Required probability is P x< 650 Required probability is P( X > 100 -() = P 650–p 100- = P( 650-789 100-70 Z > 348 112 = P(Z < -2. 08) = P(Z > 1.34) from Z-table = 0. 0901 from Z– table = 0.0188 The probability that the mean price is less than 650 is 0.0188. b) Given, sample size(n) = 42 mean(u) = 10 s tan dard deviation(6) = 13 Required probability is P < 15 = P -- ) - r(2- = P 10 < Z < 15- 15-10 = P(-0. 50 < Z < 2. 49) -0. 50 = 0. 9936 – 0. 3085 (from Z – table = 0. 6851 The probability that the mean no.of hours a week spent playing video games is between 9 and 15 is 0. 6851. II

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
See similar textbooks
icon
Related questions
Question
100%
READ THE INSTRUCTIONS. ILLUSTRATE MEANS TO DRAW THE GRAPH NOT ANSWER IT.I ALREADY HAVE THE SOLUTION I ONLY NEED THE GRAPH. UPVOTE FOR TYPEWRITTEN ONLY.
ONLY ILLUSTRATE THE DISTRIBUTION OF MEAN. DO THIS TYPEWRITTEN FOR UPVOTE. NO UPVOTE FOR HANDWRITTEN. THANK YOU a) Given, c) Given, sample size(n) = 27 mean(µ) = 789 s tan dard deviation(6) = 348 sample size(n) = 25 mean(u) = 70 s tan dard deviation(o) = 112 Required probability is P( x < 650 Required probability is P( x > 100 -() 650-u = P 100-p = P = P| Z < 650-789 348 100-70 112 = P( Z > = P(Z < -2. 08) = P(Z > 1.34) = 0. 0188 from Z – table = 0, 0901 from Z – table The probability that the mean price is less than 650 is 0. 0188. b) Given, sample size(n) = 42 теan(и) 3D 10 s tan dard deviation(6) = 13 Required probability is P 9 < i < 15 9-u 15-u = = P 9-10 <Z< 15-10 13 = P(-0.50 < Z < 2.49) = P Z < 2.49 - Z< -0. 50 = 0. 9936 – 0. 3085 (from Z – table = 0. = 0., 6851 The probability that the mean no.of hours a week spent playing video games is between 9 and 15 is 0. 6851.
Transcribed Image Text:ONLY ILLUSTRATE THE DISTRIBUTION OF MEAN. DO THIS TYPEWRITTEN FOR UPVOTE. NO UPVOTE FOR HANDWRITTEN. THANK YOU a) Given, c) Given, sample size(n) = 27 mean(µ) = 789 s tan dard deviation(6) = 348 sample size(n) = 25 mean(u) = 70 s tan dard deviation(o) = 112 Required probability is P( x < 650 Required probability is P( x > 100 -() 650-u = P 100-p = P = P| Z < 650-789 348 100-70 112 = P( Z > = P(Z < -2. 08) = P(Z > 1.34) = 0. 0188 from Z – table = 0, 0901 from Z – table The probability that the mean price is less than 650 is 0. 0188. b) Given, sample size(n) = 42 теan(и) 3D 10 s tan dard deviation(6) = 13 Required probability is P 9 < i < 15 9-u 15-u = = P 9-10 <Z< 15-10 13 = P(-0.50 < Z < 2.49) = P Z < 2.49 - Z< -0. 50 = 0. 9936 – 0. 3085 (from Z – table = 0. = 0., 6851 The probability that the mean no.of hours a week spent playing video games is between 9 and 15 is 0. 6851.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Algebra
ISBN:
9781680331141
Author:
HOUGHTON MIFFLIN HARCOURT
Publisher:
Houghton Mifflin Harcourt
SEE MORE TEXTBOOKS