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- A ball is thrown at an initial height of 90 feet at an initial velocity of 55 feet/second at an angle of 75 degrees. Given the parametric equations y = 16t2 + Vo · Sin(0)t + ho and r = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. b. When will the object hit the ground? seconds. c. How far horizontally will the ball be when it hits the ground? feet. d. When will the ball be at its maximum height? seconds. e. What is the ball's maximum height? feet. f. How far horizontally will the ball be when it reaches its maximum height? feetA seagull flies at a velocity of 12.5 m/s relative to the air straight into the wind. vSA = 12.5 m/st = 16 mind = 5.8 km 1. If it takes the bird 16 min to travel 5.8 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive. 2. If the bird turns around and flies with the wind, how long, in minutes, will it take to return 5.8 km?A ball is thrown at an initial height of 65 feet at an initial velocity of 75 feet/second at an angle of 65 degrees. Given the parametric equations yY = - - 16t + Vo · Sin(0)t + ho and x = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. seconds. b. When will the object hit the ground? feet. c. How far horizontally will the ball be when it hits the ground? seconds. d. When will the ball be at its maximum height? e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?
- A ball is thrown at an initial height of 50 feet at an initial velocity of 65 feet/second at an angle of 75 degrees. Given the parametric equations y - 16t2 + Vo Sin(0)t + ho and x = Vo. Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 2 seconds? 111.57035 v o feet. b. When will the object hit the ground? 4.60298 v o seconds. c. How far horizontally will the ball be when it hits the ground? 77.43702 v o feet. d. When will the ball be at its maximum height? 1.96204 o seconds. e. What is the ball's maximum height? 4.61479 x feet. feet f. How far horizontally will the ball be when it reaches its maximum height? 77.63571 ×One of my questions got solved and helped me so much thank you! Here’s another one please. Two trains are 9.82km apart. They travel in opposite directions, to each other. Train A has a speed of 5.87 km/h at departure and an acceleration of 0.29m/s squared. Train B has a speed of 20.3m/s at the start and an acceleration of 0.69m/s squared. B. Determine when the trains meet.A cannon is on the edge of a vertical cliff 50 m high. The cannon then fires horizontally giving the cannon ball a speed of 420 m/s. What is the speed of impact (in m/s) of the cannon ball? O 420. O 423. O 432.
- The Ferris wheel revolves once every two minutes. It has a radius of 60 ft and its center is located 64 ft from the ground. How fast is a passenger rising at the instant when she is 94 ft above the ground? a. 2.72 ft/s c. 0.433 ft/s b. 1.57 ft/s d. 3.79 ft/sA sinx is the mathematical model for the hypothesis given for the time of flight of a projectile as a function of angle. A: the fit parameter A...A = 2V0 B: the fit parameter B...B = B was not used in the model make a plot of the time of flight for a projectile as a function of launching angle, with v0 = 3.92 m/s...which graph most matchElsa?! Bida-bida. In Arendelle, Queen Elsa loves to show magic tricks to the kids and so, sje begins her show by standing on top of Olaf, a snowman that quickly melts the moment she jumps away from it. Olaf stands 1.63 [m] tall. If Elsa jumps directly upward from Olaf's head and takes 1.94 [s] to rwach a maximum height of 5.37 [m] from where Olaf's head was, how long will it take her to reach the ground from the moment she jumps off Olaf's head? O 2.40 [s] O 3.14 [s] O 1.20 [s] O 0.74 [s]
- A ball is thrown following a projectile motion.It is known that the horizontal distance (range) the ball can travel is given by R=v0²/g sin 20 ,where r is the range (in feet) ,v0 is the initial speed (in ft/s),0 is the angle of elevation the ball is thrown and g=32 ft/s² is the acceleration due to gravity. A. Express the new range in terms of the original range when an angle 0(0A ball kicked from ground level at an initial velocity of 68 m/s and an angle θ with ground reaches a horizontal distance of 295 meters. What is the size of angle θ and what is time of flight of the ball?a. θ = 17.223⁰, t = 8.44 sb. θ = 19.372⁰, t = 4.6 sc. θ = 18.263⁰, t = 9.3 sd. θ = 16.273⁰, t = 7.3 sAdding the two vectors 2î + 7ĵ and î + ĵ gives ______. Take note that the notations i and j are the x and y components respectively a. 2î + 7ĵ b. î + 8ĵ c. î + 35ĵ d. 3î + 8ĵ