= Ryan Harmel Determination of the Empirical Formula of Magnesium Oxide Data Sheet Table 1: Empirical Formula of Magnesium Oxide Mass of empty crucible Mass of crucible with Mg Observations of reaction and product: It began to light up a in to Sub an ashy Mass of crucible and product Trial 1 15.4800 15.78579 bright orange and 15.85319 estions and Calculations: SHOW WORK on all calculations. 1. Calculate the mass of magnesium used in this experiment. Trial 1 -.7851 - 15.6800 = 0.1027 Calculate the mass of product made in this experiment. Trial 1 15.853115.4800 - 0.1731 Trial 2 14.58089 14.70532 after cooling turned Trial 2 14.7860 14.7053-14.5808 = 0.1245 Trial 2 14.7840 - 14.58 0f = 0.2

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Find the percent yield of magnesium oxide in this experiment

**Determination of the Empirical Formula of Magnesium Oxide Data Sheet**

**Data Table 1: Empirical Formula of Magnesium Oxide**

|                            | Trial 1   | Trial 2   |
|----------------------------|-----------|-----------|
| Mass of empty crucible     | 15.6800 g | 16.5808 g |
| Mass of crucible with Mg   | 15.7857 g | 16.7053 g |

**Observations of reaction and product:**
- "It began to light up a bright orange and after cooling turned into an ashy substance."

|                            | Trial 1   | Trial 2   |
|----------------------------|-----------|-----------|
| Mass of crucible and product | 15.8531 g | 16.7960 g |

**Questions and Calculations:**

**SHOW WORK on all calculations.**

1. **Calculate the mass of magnesium used in this experiment.**

   - Trial 1: 
     - \( 15.7857 - 15.6800 = 0.1057 \, \text{g} \)
   - Trial 2: 
     - \( 16.7053 - 16.5808 = 0.1245 \, \text{g} \)

2. **Calculate the mass of product made in this experiment.**

   - Trial 1: 
     - \( 15.8531 - 15.6800 = 0.1731 \, \text{g} \)
   - Trial 2: 
     - \( 16.7960 - 16.5808 = 0.2152 \, \text{g} \)

***It is vital to calculate these values correctly, or the remaining calculations will all be incorrect. Feel free to check with the instructor here before continuing with the remaining calculations.***
Transcribed Image Text:**Determination of the Empirical Formula of Magnesium Oxide Data Sheet** **Data Table 1: Empirical Formula of Magnesium Oxide** | | Trial 1 | Trial 2 | |----------------------------|-----------|-----------| | Mass of empty crucible | 15.6800 g | 16.5808 g | | Mass of crucible with Mg | 15.7857 g | 16.7053 g | **Observations of reaction and product:** - "It began to light up a bright orange and after cooling turned into an ashy substance." | | Trial 1 | Trial 2 | |----------------------------|-----------|-----------| | Mass of crucible and product | 15.8531 g | 16.7960 g | **Questions and Calculations:** **SHOW WORK on all calculations.** 1. **Calculate the mass of magnesium used in this experiment.** - Trial 1: - \( 15.7857 - 15.6800 = 0.1057 \, \text{g} \) - Trial 2: - \( 16.7053 - 16.5808 = 0.1245 \, \text{g} \) 2. **Calculate the mass of product made in this experiment.** - Trial 1: - \( 15.8531 - 15.6800 = 0.1731 \, \text{g} \) - Trial 2: - \( 16.7960 - 16.5808 = 0.2152 \, \text{g} \) ***It is vital to calculate these values correctly, or the remaining calculations will all be incorrect. Feel free to check with the instructor here before continuing with the remaining calculations.***
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