رو V レス Question 4 dx2 0=30° 11 tan O tan 30° COS =2. Find the radius of curvature [15] (a) Given a = 1 + sin 0, y = sin 0-cos 20, d²y dx2 show that and the coordinates of the centre of curvature for the point on this curve where 0 = 30°. (b) Find the range of values of x for which the following series is absolutely convergent X x2 2:3 24 x5 2 x 5 + 3 x 52 4 x 53 + 5 x 54 + 6 x 55 Question 5 (a) If V = In(x² + y²). Prove that -743²)-2x( (x²+y2)2 a²v av + = 0. მე2 Jy2 [10] [15] 2. Jy 27 Jx (b) Find the sum of the series 242-202 2(x²+2)-2y(24) 2x2 x²-2y2 (x²+y2)² 8 1+2" n=1 3n-1 Jaz 4 буг [10] - 2y²-2x² 2x²=2yz 2 +-

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.6: Parametric Equations
Problem 5ECP: Write parametric equations for a cycloid traced by a point P on a circle of radius a as the circle...
Question
رو
V
レス
Question 4
dx2
0=30°
11
tan O
tan 30°
COS
=2. Find the radius of curvature
[15]
(a) Given a = 1 + sin 0, y = sin 0-cos 20,
d²y
dx2
show that
and the coordinates of the centre of curvature
for the point on this curve where 0 = 30°.
(b) Find the range of values of x for which the following
series is absolutely convergent
X
x2
2:3
24
x5
2 x 5
+
3 x 52
4 x 53
+
5 x 54
+
6 x 55
Question 5
(a) If V = In(x² + y²). Prove that
-743²)-2x(
(x²+y2)2
a²v av
+
= 0.
მე2
Jy2
[10]
[15]
2. Jy
27
Jx
(b) Find the sum of the series
242-202
2(x²+2)-2y(24)
2x2
x²-2y2
(x²+y2)²
8 1+2"
n=1
3n-1
Jaz
4
буг
[10]
- 2y²-2x² 2x²=2yz
2
+-
Transcribed Image Text:رو V レス Question 4 dx2 0=30° 11 tan O tan 30° COS =2. Find the radius of curvature [15] (a) Given a = 1 + sin 0, y = sin 0-cos 20, d²y dx2 show that and the coordinates of the centre of curvature for the point on this curve where 0 = 30°. (b) Find the range of values of x for which the following series is absolutely convergent X x2 2:3 24 x5 2 x 5 + 3 x 52 4 x 53 + 5 x 54 + 6 x 55 Question 5 (a) If V = In(x² + y²). Prove that -743²)-2x( (x²+y2)2 a²v av + = 0. მე2 Jy2 [10] [15] 2. Jy 27 Jx (b) Find the sum of the series 242-202 2(x²+2)-2y(24) 2x2 x²-2y2 (x²+y2)² 8 1+2" n=1 3n-1 Jaz 4 буг [10] - 2y²-2x² 2x²=2yz 2 +-
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