Rs L Rp Suppose you want to make fabrication of a capacitor by technique making a thin layer. The capacitor You can't just do it. It's just a capacitor, but there is other components. Capacitors with capacity C It's modeled as in side image. Inductor L and resistors, R, R, What's on this network possibly derived from parasitic inductor, losses, and leakage from material resistance Dielectric used. To prove this model and measure the magnitude, You can measure it using the Impedance Analyzer (IA), That is, by making a Bode plot from such a capacitor. The construction of the IA is shown in the following block diagram, with Z(w)ls the impedance value of the capacitor. you make tsb, namely by varying the frequency of oscillators, so Im 0(@) = tan Re that obtained impedance Z(@) = VRE² + Im? impedance of real components and imaginary components. Known resistance, reactance inductive and, with Re and Im It is the 1 XR = R, X, = joL, X_ = joC and capacitive reactance is

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4. Voltage across capacitor is vc. With ve and it as a set of state variables derive the state model. $4, R₁ vic R₂

5. Find Idc, Vdc and the capacitance that will force the Vr(pp) to 3mV. Draw the output waveform across the capacitor. Fin=60HZ. diode resistance is Si 2 ohms each Si Si 1.2k Si RLad Vs = 40Vrms

4- Design a boost converter that will have an output of 60 V from a 24-V source. Design for continuous inductor current and an output ripple voltage of less than one percent. The load is a resistance of 50 2. Assume ideal components for this design. VL ooooo ip - ^

Question 1: In the circuit shown below, the output (Vo = 10V Max.) Unipolar. The frequency of Primary is 60 Hz. The diodes are Silicon with VD = 0.7V. a. Sketch the output without a Capacitor. b. Determine Voc without a Capacitor. c. Sketch Vs (at the Secondary). d. Determine Voc with a Capacitor of 10 uF across RL. e. Determine the RMS Value of Vp (at the Primary). f. PIV (Peak Inverse Voltage). 10:1 Output C. 22 k1 All diodes are IN4001. | 00000

The input voltage (vin) of the following circuit is a sinusoidal signal with an amplitude of 2Vrms,consider a silicon diode.graph the output voltage ?? and the current across the resistor.

Facts: Facts about Clampers A clamper is an electronic circuit that fixes either the positive or the negative peak excursions of a signal to a defined value by shifting its DC value. The clamper does not restrict the peak-to-peak excursion of the signal, it moves the whole signal up or down so as to place the peaks at the reference level. A diode clamp (a simple, common type) consists of a diode, which conducts electric current in only one direction and prevents the signal from exceeding the reference value; and a capacitor, which provides a DC offset from the stored charge. The capacitor forms a time constant with the resistor load, which determines the range of frequencies over which the clamper will be effective. Question: A clamping circuit has to have an independent source, a diode, a resistor, and a capacitor. To keep a constant voltage on the capacitor over the period of the input, the RC time constant must be large. A design rule of thumb is to make the RC time constant at…

A clamper circuit has 20 Vp-p. 100Hz square wave input voltage. The circuit consists of silicon diode IN4001 and 3V battery as shown in Figure 1 C. 0.1 µF D R Vi(t) 50 k2 Vo(t) 3 V Figure 1 a) Find the output voltage for all input voltages values. b) Sketch the output waveform, Vo(t).

A clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Vaue (t). 10 k. 8V 10 kN. D2 RL Vourlt) Vin= Vin(t) Ims D1 6V -8V 4V Page | 1