Round each z-score to the nearest hundredth. A data set has a mean of  x = 6.2  and a standard deviation of 2.2. Find the z-score for each of the following. (a)    x = 6.2 (b)    x = 7.2 (c)    x = 9.0 (d)    x = 5.0

Required information Consider the following factors. 1. (FIP,21%,34) 2. (A/G,21%,45) Find the numerical values of the factors using the appropriate formula. The numerical value of factor 1 is The numerical value of factor 2 is

1. What percent of the area under the standard normal curve is within one standard deviation of (above or below) the mean?  2. What does this tell you about scores that are more than one standard deviation away from the mean?

What is the standard deviation of the following distribution: Probability           Possible Outcome     .20                          19%     .65                         13%     .15                          -8%

Consider the following POPULATION of returns: 5%, -4%, -3%, and 12%. What is the standard deviation of this population of returns? O A. 0.42% O B. 0.56% OC. 6.50% O D. 7.51%

You have two instruments and have measured the unknowns on the two instruments. You find: Unknows to compare between instruments Concentrations from Instrument 1 Concentrations from Instrument 2 Unknown 1 15.1 16.5 Unknown 2 25.3 22.1 Unknown 3 30.2 24.7 What is the t-calc value for the comparison between these two instruments?

Dividing the analysis amount by the base amount and multiplying the result by 100.

Using the following returns, calculate the arithmetic average returns, the variances, and the standard deviations for X and Y. Year X Y 1 15% 21% 2 26 36 3 7 13 4 -13 -26 5 11 15

Assuming that the rates of return associated with a given asset investment are normally distributed; that the expected​ return, r​, is 18.7​%; and that the coefficient of​ variation, CV​, is 1.88​, answer the following​ questions:   a. Find the standard deviation of​ returns, sigma Subscript rσr. b. Calculate the range of expected return outcomes associated with the following probabilities of​ occurrence: (1)​ 68%, (2)​ 95%, (3)​ 99%.

How were you able to find a D/V of 9.7% and D/V of 20%?