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ROBLEMS: 1. For each 'H NMR Spectrum below, a sub-unit can be distinguished based on the splitting patterns of the signals. Only one sub-unit is really discernible in each spectrum, ignore the other signals. a. 1H NMR Spectrum (100 MHz, CDCI, solution) Singlet Tuartet darut TMS 10 9 8 7 6 5 4 3 2 1 0 (ppm) b. 1H NMR Spectrum (200 MHz, CDCI, solution) expansion quartet singust triplet 4.0 2.0 ppm TMS 10 9 8 7 6 5 4 3 2 0 (ppm)

ROBLEMS: 1. For each 'H NMR Spectrum below, a sub-unit can be distinguished based on the splitting patterns of the signals. Only one sub-unit is really discernible in each spectrum, ignore the other signals. a. 1H NMR Spectrum (100 MHz, CDCI, solution) Singlet Tuartet darut TMS 10 9 8 7 6 5 4 3 2 1 0 (ppm) b. 1H NMR Spectrum (200 MHz, CDCI, solution) expansion quartet singust triplet 4.0 2.0 ppm TMS 10 9 8 7 6 5 4 3 2 0 (ppm)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can I get the answers for a and b please.

PROBLEMS: C. 1. For each 'H NMR Spectrum below, a sub-unit can be distinguished based on the splitting patterns of the signals. Only one sub-unit is really discernible in each spectrum, ignore the other signals. a. 1H NMR Spectrum (100 MHz, CDCl3 solution) singlet quartet darout TMS 10 9 8 7 6 5 4 3 2 1 b. 1H NMR Spectrum (200 MHz, CDCl 3 solution) expansion quarket singlest triput 4.0 2.0 ppm 10 9 8 7 6 5 4 3 2 1 66 0 S (ppm) TMS 0 8 (ppm)
Transcribed Image Text:PROBLEMS: C. 1. For each 'H NMR Spectrum below, a sub-unit can be distinguished based on the splitting patterns of the signals. Only one sub-unit is really discernible in each spectrum, ignore the other signals. a. 1H NMR Spectrum (100 MHz, CDCl3 solution) singlet quartet darout TMS 10 9 8 7 6 5 4 3 2 1 b. 1H NMR Spectrum (200 MHz, CDCl 3 solution) expansion quarket singlest triput 4.0 2.0 ppm 10 9 8 7 6 5 4 3 2 1 66 0 S (ppm) TMS 0 8 (ppm)
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