road is designed for a design speed of 65 mph. The road has a total of 8 lanes across both rections. Answer the following questions: prizontal alignment: (1) If a superelevation of 6% is used, calculate the minimum curve radius for that road. (2) Use the minimum design value, calculate the lateral clearance distance. ertical alignment: (3) Suppose the profile view of that road has an initial grade of -3% and a final grade of +4%. What is the minimum length of the vertical curve under the same design speed?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A road is designed for a design speed of 65 mph. The road has a total of 8 lanes across both
directions. Answer the following questions:
Horizontal alignment:
(1) If a superelevation of 6% is used, calculate the minimum curve radius for that road.
(2) Use the minimum design value, calculate the lateral clearance distance.
Vertical alignment:
(3) Suppose the profile view of that road has an initial grade of -3% and a final grade of
+4%. What is the minimum length of the vertical curve under the same design speed?
(4) Use that min. length as the design value (L), find the elevation of the curve that is ¼ of L
away from PVC. Elevation of PVC = 1,000 ft.
Transcribed Image Text:A road is designed for a design speed of 65 mph. The road has a total of 8 lanes across both directions. Answer the following questions: Horizontal alignment: (1) If a superelevation of 6% is used, calculate the minimum curve radius for that road. (2) Use the minimum design value, calculate the lateral clearance distance. Vertical alignment: (3) Suppose the profile view of that road has an initial grade of -3% and a final grade of +4%. What is the minimum length of the vertical curve under the same design speed? (4) Use that min. length as the design value (L), find the elevation of the curve that is ¼ of L away from PVC. Elevation of PVC = 1,000 ft.
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PLEASE ANSWER QUESTION 4 stated above 

 

HOW DID WE OBTAIN 0.38 and 0.07 for solution 3. L=0.38(0.07×104.63)^1/2

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