*** ring Comparison Examples: # evaluates to True # evaluates to False "apple" < "banana" "apple" == "Apple" "apple" < "Apple" # evaluates to False "Zoo" < "apple" "apple" < "apples" #evaluates to True 11 # evaluates to True N a e oo search hp 2

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

I do not understand why these answer so are what they are. This has to do with string comparison an and Ascii. 

***
ring Comparison
Examples:
# evaluates to True
# evaluates to False
"apple" < "banana"
"apple" == "Apple"
"apple" < "Apple" # evaluates to False
"Zoo" < "apple"
"apple" < "apples" #evaluates to True
11
# evaluates to True
N
a e oo
search
hp
2
Transcribed Image Text:*** ring Comparison Examples: # evaluates to True # evaluates to False "apple" < "banana" "apple" == "Apple" "apple" < "Apple" # evaluates to False "Zoo" < "apple" "apple" < "apples" #evaluates to True 11 # evaluates to True N a e oo search hp 2
Expert Solution
Step 1

Answer:

The string comparison is basically compared with their ASCII values. Here, the ASCII value for the given strings are:

Apple – 65 112 112 108 101

apple – 97 112 112 108 101

banana – 98 97 110 97 110 97

Zoo – 90 111 111

apples – 97 112 112 108 101 115

Step 2

Now, compare the first statement in the given image

“apple” < “banana”

Here, the first letter of both strings are different so checks the ASCII value of “a” (97) is less than the ASCII value of “b” (98). The condition becomes true. So it will display the “True” as an output.

Step 3

Compare the second statement in the given image

“apple” == “Apple”

Here, the first letter of both strings are different so checks the ASCII value of “a” (97) is equal to the ASCII value of “A” (65). The condition becomes false. So it will display the “False” as an output.

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