Ribose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four- membered, five-membered, or six-membered ring. To determine which ring is formed, ribose is treated with methanol in the presence of an acid catalyst. The products are then isolated and treated with NaIO4 then with H3O+. OH HO OH OH Ribose, C5H10O5 H MeOH H* A & B isomeric cyclic acetals with formula C6H₁2O5 1. NalO4 2. H₂O* MeOH products Assuming that ribose formed a six-membered ring cyclic hemiacetal, draw the structure of the sodium periodate digestion products. • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.

Draw the cyclic forms of beta-1,3'-d-ditalose

1)  The starch in 25kg (~1 bushel) of corn is hydrolyzed and in the process 1.8kg of water (H2O) is consumed.  How many moles of glucose (C6H12O6) would you expect to be produced? C6H12O6      ->     2 CO2  +  2 C2H5OH. 2)  If the glucose from the above hydrolysis is fermented, how many moles of ethanol (C2H5OH) would result?  How many grams? 3)  If ethanol has a density of 0.789g/ml, what would the volume of the ethanol be in ml?  What would the volume be in gallons (1gal = 3785ml)? 4)  The above ethanol could be converted to Vodka by diluting to 50% ethanol (adding enough water to double the volume).  What would the volume of the resulting Vodka be in ml?  If the volume of a “shot” of Vodka is 30ml, how many shots of vodka could be produced from a bushel of corn?

Ribose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. When D-ribose is treated with methanol in the presence of an acid catalyst, two cyclic acetals, A and B, are formed, both with molecular formula C,H,0, These are separated, and each is treated with sodium periodate (Section 10.8C) followed by dilute aqueous acid. Both A and B yield the same three products in the same ratios. он о CHO СНО H+ CH,OH A +B ÕH 1. NalO, 2. H,0* НО CHO + CHOH + CH,OH ÕH CH,OH Isomeric cyclic acetals with molecular formula CH12O, D-Ribose (C;H1605) From this information, deduce whether the cyclic hemiacetal formed by D-ribose is four- membered, five-membered, or six-membered.

Draw the structure of the repeating unit of the polyamide formed from this reaction. CI H H₂N NH₂ You do not have to consider stereochemistry. + CI polymerization

Identify the organic functional group and reaction type for the following reaction. The reactant is a(n) - carboxylic acid hexose - Aldohexose - aldotetrose -deoxyhexose -carboxylic acid tetrose - ketohexose The product is a(n) - carboxylic acid tetrose - aldotetrose -alcohol hexose -aldohexose -carboxylic acid hexose - alcohol tetrose The reaction type is - hemiacetal formation -hydrolysis -oxidation( Benedict’s) -acetal formation -reduction( hydrogenation) - mutarotation

Sugar alcohols (alditols) are formed by chemically reducing aldoses or ketoses. Which one of the following sugars will give a negative Benedict's Test? aldopentoses alditols 2- Ketopentoses an aldose undergoing mutarotation in solution

what is the enantiomer of this sugar