reviously, 3​% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3​% today. She randomly selects 150 pregnant mothers and finds that 2 of them smoked 21 or more cigarettes during pregnancy. Test the​ researcher's statement at the α=0.05 level of significance. What are the null and alternative​ hypotheses?   H0​: ▼   pp sigmaσ muμ ▼   less than< equals= not equals≠ greater than> nothing versus H1​: ▼   pp sigmaσ muμ ▼   less than< not equals≠ greater than> equals= nothing ​(Type integers or decimals. Do not​ round.) Because np01−p0=nothing ▼   greater than> not equals≠ equals= less than< ​10, the normal model ▼   may may not be used to approximate the​ P-value. ​(Round to one decimal place as​ needed.) Find the​ P-value.   ​P-value=nothing ​(Round to three decimal places as​ needed.) Is there sufficient evidence to support the​ obstetrician's statement?     A. Yes​, reject the null hypothesis because the​ P-value is less than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3​%.   B. Yes​, do not reject the null hypothesis because the​ P-value is greater than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3​%.   C. No​, do not reject the null hypothesis because the​ P-value is greater than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3​%.   D. No​, reject the null hypothesis because the​ P-value is less than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3​%.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Question
reviously,
3​%
of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than
3​%
today. She randomly selects
150
pregnant mothers and finds that
2
of them smoked 21 or more cigarettes during pregnancy. Test the​ researcher's statement at the
α=0.05
level of significance.
What are the null and alternative​ hypotheses?
 
H0​:
 
pp
sigmaσ
muμ
 
less than<
equals=
not equals≠
greater than>
nothing
versus
H1​:
 
pp
sigmaσ
muμ
 
less than<
not equals≠
greater than>
equals=
nothing
​(Type integers or decimals. Do not​ round.)
Because
np01−p0=nothing
 
greater than>
not equals≠
equals=
less than<
​10,
the normal model
 
may
may not
be used to approximate the​ P-value.
​(Round to one decimal place as​ needed.)
Find the​ P-value.
 
​P-value=nothing
​(Round to three decimal places as​ needed.)
Is there sufficient evidence to support the​ obstetrician's statement?
 
 
A.
Yes​,
reject
the null hypothesis because the​ P-value is
less
than
α.
There
is
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3​%.
 
B.
Yes​,
do not reject
the null hypothesis because the​ P-value is
greater
than
α.
There
is
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3​%.
 
C.
No​,
do not reject
the null hypothesis because the​ P-value is
greater
than
α.
There
is not
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3​%.
 
D.
No​,
reject
the null hypothesis because the​ P-value is
less
than
α.
There
is not
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3​%.
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