Review | Constants Block 1, of mass m1 = 6.90 kg , moves along a frictionless air track with speed vi = 17.0 m/s. It collides with block 2, of mass m2 = 53.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) Part C What is the change AK = Kfinal - Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. Figure 1 of 1 • View Available Hint(s) Before collision: m2 m AK = 938.348 J Submit Previous Answers After collision: X Incorrect; Try Again; 4 attempts remaining Provide Feedback Next > 國

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Image Transcription for Educational Website**

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**Problem Description**

Block 1, of mass \(m_1 = 6.90 \, \text{kg}\), moves along a frictionless air track with speed \(v_1 = 17.0 \, \text{m/s}\). It collides with block 2, of mass \(m_2 = 53.0 \, \text{kg}\), which was initially at rest. The blocks stick together after the collision. (Figure 1)

**Figure Description**

*Figure 1:*

- **Before Collision:**
  - Block 1: Mass \(m_1\), velocity \(v_1\)
  - Block 2: Mass \(m_2\), initially at rest
  - Block 1 is shown moving towards Block 2.

- **After Collision:**
  - Both blocks are combined, moving together with a new velocity \(v_f\).

**Question**

**Part C:**  
What is the change \(\Delta K = K_{\text{final}} - K_{\text{initial}}\) in the two-block system's kinetic energy due to the collision?  
Express your answer numerically in joules.

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**Answer Input Section**

- **User Input:**  
  \(\Delta K = 938.348 \, \text{J}\)  

**Feedback Message**

- Incorrect; Try Again; 4 attempts remaining

(Note: Provides feedback about the user's answer submission.)

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Transcribed Image Text:**Image Transcription for Educational Website** --- **Problem Description** Block 1, of mass \(m_1 = 6.90 \, \text{kg}\), moves along a frictionless air track with speed \(v_1 = 17.0 \, \text{m/s}\). It collides with block 2, of mass \(m_2 = 53.0 \, \text{kg}\), which was initially at rest. The blocks stick together after the collision. (Figure 1) **Figure Description** *Figure 1:* - **Before Collision:** - Block 1: Mass \(m_1\), velocity \(v_1\) - Block 2: Mass \(m_2\), initially at rest - Block 1 is shown moving towards Block 2. - **After Collision:** - Both blocks are combined, moving together with a new velocity \(v_f\). **Question** **Part C:** What is the change \(\Delta K = K_{\text{final}} - K_{\text{initial}}\) in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. --- **Answer Input Section** - **User Input:** \(\Delta K = 938.348 \, \text{J}\) **Feedback Message** - Incorrect; Try Again; 4 attempts remaining (Note: Provides feedback about the user's answer submission.) ---
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