Review of complex numbers 1=R₁e z=Re Do not use AI, I need real solution, attach required graph and code wherever needed. For reference I have attached the image, but if you need any reference then check out the book by Churchill only. Ca-e2/8 22= R₂e 2122=R₁ Re(+₂) 01+02 R Saz-Re40+2x/8) The complex conjugate of z = Rei = a + bi is z= Rea-bi. which is the reflection of z across the real axis. Note that Iz²=z z=Re Re-i = R2e0 = R² => Consider a meromorphic function f : C+C (the Riemann sphere), where C = CU{0}. 1. Weierstrass Factorization Theorem: State and prove the Weierstrass Factorization Theorem. Then, use it to express an entire function f(x) with prescribed zeros {a} (without accumulation points in C) as a product involving its zeros. 2. Picard's Theorem: Prove the Great Picard Theorem: If an analytic function f has an essential singularity at a point zo, then in any neighborhood of zu, f takes on every complex value, with at most a single exception, infinitely often. 3. Nevanlinna Theory Fundamentals: Introduce the Nevanlinna characteristic function T(r, f) for a meromorphic function f. Prove the First Fundamental Theorem of Nevanlinna Theory, which relates T(r. f), the counting function N(r,a), and the proximity function m(r, a) for a value a € C. 4. Second Fundamental Theorem and Defect Relations: State the Second Fundamental Theorem of Nevanlinna Theory. Use it to derive defect relations, demonstrating that for a non-constant meromorphic function, the sum of defects for all distinct values in C is at most 2. 5. Applications to Value Distribution: Apply Nevanlinna Theory to prove that any non-constant entire function f omitting more than one value in Ĉ must be constant, thereby providing an alternative proof of the Little Picard Theorem.

ANSWER A AND B FROM PROB 4 SHOW STEPS OF COMPLEX NUMBER IN RECTANGULAR FORM

Simplify the complex number (Z^3) * ?and find the Re(z) & Im(z)

Review of complex numbers =Rje 22=R₂e z=Re 2122 R1 R₂+82) Caz-Re(+2x/8) The complex conjugate of z = Rei=a+bi is z=Re-a-bi, which is the reflection of z across the real axis. Note that Do not use AI, I need real solution, attach required graph and code wherever needed. For reference I have attached the image, but if you need any reference then check out the book by Churchill only. Ca-e2/8 |z2=zz Re Re = R2e0 = R2 => |z|= √√zz = √√a² + b² = R. Problem 5: The Cauchy Integral Formula and Its Consequences Statement: Let D be a bounded, simply connected domain in C with a piecewise smooth boundary D, and let f: D→ C be holomorphic on D and continuous on D. 1. Cauchy Integral Formula: Prove the Cauchy Integral Formula: For any z € D, 2. Cauchy's Estimates: f(C) f(z) = 2mi Using the Cauchy Integral Formula, derive Cauchy's estimates for the derivatives of f. Specifically, show that for any n≥ 0, |f(") (=)|≤ n!M R where M = maxcap |f(C) and R is the distance from z to OD. 3. Taylor and Laurent…

I need it solved for preparation to tomorrow exam help Please ! ? I have answers in the system without step by step help !

Review of complex numbers Do not use AI, I need real solution, attach required graph and code wherever needed. For reference I have attached the image, but if you need any reference then check out the book by Churchill only. Z2=R2e2 21=R1e01 z=Reia (8=e²xi/8 01+02 R R Z122 R1 R2e1+82) $82=Rei(+2x/8) The complex conjugate of z = Reie = a + bi is Z= Rea- bi, which is the reflection of z across the real axis. Note that |z2z-Z Re Re-i = R²e = R² => |z|= √√√zz = √√√a² + b² = R. Let D and D' be simply connected domains in C, and let f : DD' be a biholomorphic (conformal) map. 1. Preservation of Laplace's Equation: Show that if u : D'→R is a harmonic function on D', then u of is a harmonic function on D. 2. Conformal Invariance of the Laplacian: • Prove that the Laplacian operator is conformally invariant up to a scaling factor. Specifically, demonstrate that for f: DD' biholomorphic and u twice continuously differentiable, A(uf) = f(z)|(Au) of. 3. Dirichlet Problem and Conformal Mapping: ⚫…

Awnser pl

find all complex-number solutios (x+5)2 = -108