Retention Test Scores A sample of non-English majors at a selected college was used in a study to see if the student retained more from reading a 19th-century novel or by watching it in DVD form. Each student was assigned one novel to read and a different one to watch, and then they were given a 20-point written quiz on each novel. The test results are shown below. At a = 0.05, can it be concluded that the book scores are higher than the DVD scores? Assume the variables are normally distributed. ВBook 90 80 90 75 80 90 84 86 DVD 85 72 80 80 70 75 80 79 Send data to Excel Part: 0 / 4 Part 1 of 4 (a) State the hypotheses and identify the claim with the correct hypothesis. Ho: (Choose one) H: (Choose one) This hypothesis test is a (Choose one) test.

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Retention Teat ScoresAample of non-Engliah majora ata elected college wa ued ina atudy to see if the
student retained more from reading - 19th century novel or by watching it in DVD form. Each student wa Bigned
one novel to read and a different one to watch, and then they were given a 20-point written quiz on each novel. The
test results are ahoven below. At a= 0.01. can it be concluded that the book acores are higher than the DVD sores?
Assume rhe variahle are normanily dieertbuted.
gbaxCOhKa0S18zQQvuJZZ0CtHs.. Q
Book
84 s6
88 92
90
80
90
75
80
90
DVD
85
72
80
80
70
75
90
79
77
93
(Senn nta to Exce
(-) Statu the hypothuaua nd iduntify th claim with the correct hypothwaa.
(b) Find th P-value.
(e) Make the decinion.
(d) Summarize the reaulta.
(a) State the hypotheses and identify the claim with the correct hypothesis.
The null hypothesis H, is the statement that the difference between the matched pairs is zero. This is equivalent to un = 0.
The alternative hypothesis H, is the statement that the difference between the matched pairs is not zero. Since we are interested to see if the
reading quiz scores are higher than the DVD quiz scores, the differences must be greater than zero. This is equivalent to un>0.
The problem asks if it can "be concluded that the book scores are higher than the DVD scores." Hence, the claim is the alternative hypothesis
(b) Find the P-value.
The TI-83 Plus/TI-84 Plus graphing calculators do not provide a t test for the difference between means for dependent samples. However, the
differences between the paired data in two lists can be calculated in a third list and then the single sample t test can be applied on that third
list of data.
L1
L2
L3
EDIT CALC TESTS
90
85
1: Z-Test...
2: T-Test..
80
72
90
80
10
3: 2-SampZTest...
4: 2-SampTTest...
5: 1-PropZTest...
6: 2-PropZTest...
7Į ZInterval...
75
80
-5
80
70
10
90
75
84
80
L3 (7)- 4
T-Test
Inpt: Data
Stats
List: L,
Freq: 1
u: + H < H, > Ho
Calculate Draw
Enter the book scores in the list L1 and DVD scores data in the list L2. Move the cursor to the top of the L3 column so that L3 is highlighted.
Type L1 - L2, then press ENTER.
Then enter in the appropriate fields in the calculator.
4, = 0, List = L3, Freq = 1, right-tailed test.
Press the following keystrokes into either the TI-83 Plus or the TI-84 Plus calculator.
STAT OO20ENTER) OO O 2and 3O MAPHA 100D ENTER
O ENTER)
t = 4.367236588
p =9.0216862E-4
x =7.4
Your screen should display the following (or very similar) result.
T-Test
u >0
t = 4.367236588
Sx =5.358275013
2 = 10
p = 9.0216862E-4
x = 7.4
The P-value is 0.0009 rounded to 4 decimal places.
Sx = 5.358275013
(c) Make the decision.
Hence, the null hypothesis is rejected as the P-value is less than a= 0.01.
n = 10
(d) Summarize the results.
Since the null hypothesis was rejected, there is enough evidence to support the claim.
The P-value is 0.0009 rounded to 4 decimal places.
Transcribed Image Text:Sample Question Retention Teat ScoresAample of non-Engliah majora ata elected college wa ued ina atudy to see if the student retained more from reading - 19th century novel or by watching it in DVD form. Each student wa Bigned one novel to read and a different one to watch, and then they were given a 20-point written quiz on each novel. The test results are ahoven below. At a= 0.01. can it be concluded that the book acores are higher than the DVD sores? Assume rhe variahle are normanily dieertbuted. gbaxCOhKa0S18zQQvuJZZ0CtHs.. Q Book 84 s6 88 92 90 80 90 75 80 90 DVD 85 72 80 80 70 75 90 79 77 93 (Senn nta to Exce (-) Statu the hypothuaua nd iduntify th claim with the correct hypothwaa. (b) Find th P-value. (e) Make the decinion. (d) Summarize the reaulta. (a) State the hypotheses and identify the claim with the correct hypothesis. The null hypothesis H, is the statement that the difference between the matched pairs is zero. This is equivalent to un = 0. The alternative hypothesis H, is the statement that the difference between the matched pairs is not zero. Since we are interested to see if the reading quiz scores are higher than the DVD quiz scores, the differences must be greater than zero. This is equivalent to un>0. The problem asks if it can "be concluded that the book scores are higher than the DVD scores." Hence, the claim is the alternative hypothesis (b) Find the P-value. The TI-83 Plus/TI-84 Plus graphing calculators do not provide a t test for the difference between means for dependent samples. However, the differences between the paired data in two lists can be calculated in a third list and then the single sample t test can be applied on that third list of data. L1 L2 L3 EDIT CALC TESTS 90 85 1: Z-Test... 2: T-Test.. 80 72 90 80 10 3: 2-SampZTest... 4: 2-SampTTest... 5: 1-PropZTest... 6: 2-PropZTest... 7Į ZInterval... 75 80 -5 80 70 10 90 75 84 80 L3 (7)- 4 T-Test Inpt: Data Stats List: L, Freq: 1 u: + H < H, > Ho Calculate Draw Enter the book scores in the list L1 and DVD scores data in the list L2. Move the cursor to the top of the L3 column so that L3 is highlighted. Type L1 - L2, then press ENTER. Then enter in the appropriate fields in the calculator. 4, = 0, List = L3, Freq = 1, right-tailed test. Press the following keystrokes into either the TI-83 Plus or the TI-84 Plus calculator. STAT OO20ENTER) OO O 2and 3O MAPHA 100D ENTER O ENTER) t = 4.367236588 p =9.0216862E-4 x =7.4 Your screen should display the following (or very similar) result. T-Test u >0 t = 4.367236588 Sx =5.358275013 2 = 10 p = 9.0216862E-4 x = 7.4 The P-value is 0.0009 rounded to 4 decimal places. Sx = 5.358275013 (c) Make the decision. Hence, the null hypothesis is rejected as the P-value is less than a= 0.01. n = 10 (d) Summarize the results. Since the null hypothesis was rejected, there is enough evidence to support the claim. The P-value is 0.0009 rounded to 4 decimal places.
Retention Test Scores A sample of non-English majors at a selected college was used in a study to see if the student retained
more from reading a 19"-century novel or by watching it in DVD form. Each student was assigned one novel to read and a
different one to watch, and then they were given a 20-point written quiz on each novel. The test results are shown below. At
a = 0.05, can it be concluded that the book scores are higher than the DVD scores? Assume the variables are normally distributed.
Вook
90
80
90
75
80
90
84
86
DVD
85
72
80
80
70
75
80
79
Send data to Excel
Part: 0 / 4
Part 1 of 4
(a) State the hypotheses and identify the claim with the correct hypothesis.
H.:
|(Choose one)
H:
(Choose one)
This hypothesis test is a (Choose one) V
test.
Transcribed Image Text:Retention Test Scores A sample of non-English majors at a selected college was used in a study to see if the student retained more from reading a 19"-century novel or by watching it in DVD form. Each student was assigned one novel to read and a different one to watch, and then they were given a 20-point written quiz on each novel. The test results are shown below. At a = 0.05, can it be concluded that the book scores are higher than the DVD scores? Assume the variables are normally distributed. Вook 90 80 90 75 80 90 84 86 DVD 85 72 80 80 70 75 80 79 Send data to Excel Part: 0 / 4 Part 1 of 4 (a) State the hypotheses and identify the claim with the correct hypothesis. H.: |(Choose one) H: (Choose one) This hypothesis test is a (Choose one) V test.
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