researcher using camera traps estimates a daily detection probability for mink of 0.09 in an occupancy modeling framework. During a 5-day study, what are the odds that she did not detect a mink at a site where one actually occurred?
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A researcher using camera traps estimates a daily detection probability for mink of 0.09 in an occupancy modeling framework. During a 5-day study, what are the odds that she did not detect a mink at a site where one actually occurred?
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- If a researcher conducts 37 tests, each with an alpha = .05, what is the probability that the researcher will get at least 1 statistically significant result, even if there's truly no effect? Report your answer as a proportion (not percentage), rounded to 2 decimal places. Hint: review the "P-Hacking" Crash Course video, specifically the part about family-wise errorYou work for a company that produces electronics with integrated circuits. One of your products is called a "shift register." This product is designed to automatically shut down if its operating temperature exceeds 175 degrees Celsius. The manufacturing process has been designed to have a standard deviation of o = 0.4 degrees Celsius. You test a random sample 20 shift registers, and you record the following shut- down temperatures. Construct a 98% confidence interval for the overall mean shutdown-temperature. 175.14 174.25 175.18 175.59 174.93 175.56 174.46 174.6 174.83 175.2 174.87 174.14 174.51 174.52 175.46 175.11 175.24 175.05 174.97 174.4 (Checksum: 3498.01) a) Find the critical value and oã . Critical Value: b) Find the confidence interval:Teenagers who do not sleep well or long enough may have a higher risk of raised blood pressure, which could lead to cardiovascular disease later in life. The odds of raised blood pressure increase 3.5 times for those who have trouble falling asleep at night or who wake up too early and 2.5 times for those with sleeping periods of fewer than 6.5 hours. A health psychologist is interested in studying teenagers who have diastolic blood pressure scores in the top 20%. Diastolic blood pressure scores for teenagers follow a normal distribution with μ = 72 and σ = 10. Use the Distributions tool to help answer the questions that follow. The minimum z-score necessary to be in the top 20% of the diastolic blood pressure distribution is z =0.842 . Use this z-score to determine X, the corresponding diastolic blood pressure score. X = 80.42 This score, X, is the 80th percentile of diastolic blood pressure scores among teenagers. The percentile rank of this score is 80%…
- The business college wants to determine the proportion of business students who have extended time between classes. If the proportion differs from 30%, then the lab will modify a proposed enlargement of its facilities. Suppose a hypothesis test is conducted and the test statistic is 2.5. Find the P-value for a two-tailed test of hypothesis.If charge rates for annual tutoring services has a standard deviation of $1000, what is the probability that the mean charge rate of 300 randomly selected tutoring services will be within $80 of the mean charge rate of all tutoring servicesYou work for a company that produces electronics with integrated circuits. One of your products is called a "shift register." This product is designed to automatically shut down if its operating temperature exceeds 175 degrees Celsius. The manufacturing process has been designed to have a standard deviation of o = 0.4 degrees Celsius. You test a random sample 16 shift registers, and you record the following shut- down temperatures. Construct a 80% confidence interval for the overall mean shutdown-temperature. 174.99 174.76 174.99 174.61 174.86 174.41 175.54 174.13 174.96 174.78 174.84 174.67 174.87 175.52 174.88 175.35 (Checksum: 2798.16) a) Find the critical value and ₂. Critical Value: σz: b) Find the confidence interval:
- Most hospitals now have signs posted everywhere banning cell phone use. These bans originate from studies on earlier versions of cell phones. In one such experiment, out of 510 tests with cell phones operating at near-maximum power, 160 disrupted a piece of medical equipment enough to hinder interpretation of data or cause equipment to malfunction. Test whether this estimate is different from random chance What is H0, HA, Test statistic?From independent surveys of two populations, 90% confidence intervals are constructed. What is the probability that neither interval contains the respective population mean? What is the probability that both do?A two-tailed hypothesis test for the population mean has two critical values. may have one or two critical values. has only one critical value. O may have more than two critical values.
- A researcher selects a sample from a population with a mean of 50 and administers a treatment to the individuals in the sample. If the treatment is expected to decrease scores, what is the correct statement for the alternative hypothesis for a one tailed testA decade-old study found that the proportion of high school seniors who believed that "getting rich" was an important personal goal was 70%. A researcher decides to test whether or not that percentage still stands. He finds that, among the 205 high school seniors in his random sample, 125 believe that "getting rich" is an important goal. Can he conclude, at the 0.01 level of significance, that the proportion has indeed changed? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis and the alternative hypothesis . (b) Determine the type of test statistic to use. (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three or more decimal places.) (e) Can we conclude that the proportion of high school seniors…The Jamestown Steel Company manufactures and assembles desks and other office equipment at several plants. The weekly production of the Model A325 desk follows a normal probability distribution, with a mean of 200 and a standard deviation of 16. Recently, due to market expansion, new production methods have been introduced and new employees hired. The vice president of manufacturing would like to investigate whether there has been a change in the weekly production of the Model A325 desk. Is the mean number different from 200? The mean number of desks produced last year (50 weeks, because the plant was shut down two weeks for vacation) is 203.5. Test using the.01 significance level. i. The alternate hypothesis is u200. ii. The calculated value of z is 2.55. m. The decision rule is: if the computed value of the test statistic is not between -2.58 and 2.58, reject the null hypothesis. desks produced Multiple Choice (1). (i1). and (i) are all correct statements. (i) is a correct statement…