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- Given the network address 148.211.93.128/25, develop a scheme for 3 subnets with at most 10 hosts each. Show the subnet mask and CIDR notation for the subnet scheme. Show the 1st, 2nd, and 3rd subnet addresses and list the range of available IP addresses for each subnet.Given the network address 32.0.0.0/3, develop a scheme for 1000 subnets with at most 2000 hosts each. Show the subnet mask and CIDR notation for the subnet scheme. Show the 1st, 2nd, and 1000th subnet address and list the range of available IP addresses for each.Given each IP address and mask, supply the following information for each of these 9 examples: a) Size of the network part of the address (No. of network bits). b) Size of the subnet part of the address (No. of subnet bits). c) Size of the host part of the address (No. host bits). d) The number of hosts per subnet e) The number of subnets in this network f) The subnet address g) First address h) The broadcast address 1. 10.180.10.18, mask 255.192.0.0 2. 10.200.10.18, mask 255.224.0.0 3. 172.31.100.100, mask 255.255.224.0 4. 172.31.200.10, mask 255.255.248.0 5. 192.168.100.100, mask 255.255.255.240 6. 192.168.100.100, mask 255.255.255.248 7. 192.168.15.230, mask 255.255.255.252 A-h has been solved Kindly solve 1-7
- Given each IP address and mask, supply the following information for each of these 9 examples: a) Size of the network part of the address (No. of network bits). b) Size of the subnet part of the address (No. of subnet bits). c) Size of the host part of the address (No. host bits). d) The number of hosts per subnet e) The number of subnets in this network f) The subnet address g) First address h) The broadcast address 1. 10.180.10.18, mask 255.192.0.0 2. 10.200.10.18, mask 255.224.0.0 3. 172.31.100.100, mask 255.255.224.0 4. 172.31.200.10, mask 255.255.248.0 5. 192.168.100.100, mask 255.255.255.240 6. 192.168.100.100, mask 255.255.255.248 7. 192.168.15.230, mask 255.255.255.252 1. Given each IP Address and Subnet mask, supply the following information for each of them: I. The class of IP Address II. Number of network bits III. Number of host bits IV. The appropriate subnet mask a) 10.10.2.1 number of hosts in the network 512 b) 172.160.10.2 number of hosts in the network 1200 c)…For the following CLSM subnetting problems, submit: a. bits for subnet b. bits for host C. subnet mask d. 1st, 2nd, xth subnet addresses (where x is the requested number of subnets) e. beginning and ending ip address range for each subnet listed in d. 225.10.20.0/24 - 15 Subnets, 10 HostsDesign the subnets for the branches using VLSM, according to the required minimum hostsas shown. Design also the subnet for ONE WAN link. Network address 11.0.0.0Branch Number of usable hostsBranch A 20,000Branch B 580,000Branch C 120 1. Draw and fill in the table with the subnet addresses that you have designed. [8 marks]
- Refer to figure 1; an internetwork has been assigned the address 200.201.202.0. Subnet this addresses to meet the following requirements: 120 Hosts 14 Hosts LAN Segment 1 LAN Segment 2 WAN Link 1 WAN Link 2 WAN Link 4 WAN Link 3 LAN Segment 3 LAN Segment 4 29 Hosts 6 Hosts Figure 1 Network Subnet/Mask No. of Host Address Range Broadcast Address LAN Segment LAN Segment 2 LAN Segment LAN SegmentPerform FLSM, take a network address generated from your IP : 61.03.0.0/24 and find the fixed ranges of 35 usable host addresses. Create a table having columns [No. of hosts, Network Address, Broadcast address, Valid hosts range, Subnet mask]• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 Bits
- Question 5 What is the range of host loopback addresses in IPV6? The prefix in compressed format is [1] and the prefix length is [2] bits. Specified Answer for: 1 Specified Answer for: 2Find the number of subnets and hosts per the subnet in these addresses: 16.100.0/28 Class: B Subnet Mask :24 Host=8 0.0.0/18 168.5.0/30Calculate IPV4 Address Subnets in the following given Table. Given: Host IP address: Default Subnet Mask: 255.255.255.0 196.168.10.0 New Subnet Mask: 255.255.255.192 Determine: Number of Subnets Created: per Subnet: Network Address of this Subnet: Number of Hosts IPV4 Address of First Host on this Subnet: IPV4 Broadcast Address on this Subnet: