Required InformationNOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.A truss of a power transmission line tower is shown. Given loading of L = 1.2 kN.1.60 m-2.21 m--2.97 m--2.21 m-DAllRFLLP1.20 mL1.20 mKN (Click to select)0.60 mThe portion of truss shown represents the upper part of a power transmission line tower. Determine the force in each of the memberslocated above HUJ. State whether each member is in tension (7) or compression (C).The force in member AB (FAB) isKN (Click to select)The force in member AC (FAC) isThe force in member DF (FDA) isThe force in member EF (FER) isThe force in member BD (FBD) isThe force in member DE (FDE) isThe force in member BE (FB) isThe force in member BC (FBC) isThe force in member CE (FCE) isThe force in member CH (FCH) isThe force in member EH (FEH) isThe force in member EJ (FE) isKN (Click to select) VKN (Click to select)$0.60 m10.60 mKN (Click to select)KN (Click to select) VKN (Click to select)0.60 mKN (Click to select) V10.00KN (Click to select)KN (Click to select)kN (Click to select) VKN (Click to select) V

L= 1.2 kN To find - The forces in members.

Required Information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A truss of a power transmission line tower is shown. Given loading of L = 1.2 kN. 1.60 m -2.21 m 2.97 D The force in member AC (FAC) is [ The force in member DF (FDA) is The force in member EF (FEA) is [ The force in member BD (FBD) is The force in member DE (FDE) is [ The force in member BE (FBE) is The force in member BC (FBC) is [ The force in member CE (FCE) is The force in member CH (FCH) is [ The force in member EH (FEH) is The force in member EJ (FE) is [ -2.21 m L L 1.20 m L 0.60 m 0.60 m 1.20 m KN (Click to select) KN (Click to select) 0.60 m 10.60 m The portion of truss shown represents the upper part of a power transmission line tower. Determine the force in each of the members located above HJ. State whether each member is in tension (7) or compression (C). The force in member AB (FAB) is kN (Click to select) KN (Click to select) ♥ kN (Click to select) kN (Click to select) KN (Click to select) KN (Click to select) KN (Click to select) KN (Click to select) KN (Click to select) $0.00 0.00 m KN (Click to select) ♥

Required Information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A truss of a power transmission line tower is shown. Given loading of L = 1.2 kN. 1.60 m -2.21 m 2.97 D The force in member AC (FAC) is [ The force in member DF (FDA) is The force in member EF (FEA) is [ The force in member BD (FBD) is The force in member DE (FDE) is [ The force in member BE (FBE) is The force in member BC (FBC) is [ The force in member CE (FCE) is The force in member CH (FCH) is [ The force in member EH (FEH) is The force in member EJ (FE) is [ -2.21 m L L 1.20 m L 0.60 m 0.60 m 1.20 m KN (Click to select) KN (Click to select) 0.60 m 10.60 m The portion of truss shown represents the upper part of a power transmission line tower. Determine the force in each of the members located above HJ. State whether each member is in tension (7) or compression (C). The force in member AB (FAB) is kN (Click to select) KN (Click to select) ♥ kN (Click to select) kN (Click to select) KN (Click to select) KN (Click to select) KN (Click to select) KN (Click to select) KN (Click to select) $0.00 0.00 m KN (Click to select) ♥

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Required Information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A Howe roof truss is shown. Take P₁= P₂= P3 = 600 lb. P2 300 b P1 BY CI P3 E SASHSA→→SA- The force in member AB (FAB) is The force in member AC (FAC) is The force in member BC (FBC) is The force in member CE (FCE) is The force in member BD (FBD) is The force in member BE (FB) is The force in member DF (FDA) is The force in member DE (FDE) is The force in member EF (FEA) is The force in member EG (FEG) is The force in member FG (FFG) is The force in member FH (FFH) is The force in member GH (FGH) is 300 lb 6 ft G H 6 ft Determine the force in each member of the Howe roof truss shown. State whether each member is in tension (7) or compression (C). lb (Click to select) V lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) V lb (Click to select) lb…
1. 1100 A. 30% B. 1.1 m 1.0 m A F= 255 N 0.5 m 1.5 m DGB WARNING! The figure is not drawn to scale. For the force in the chain CB, ca IMAGES NOTES DISCUSS UNITS STATS HELP PREFERENCES Part Description the magnitude of component parallel to the hinge axis of the door, (include units with answer) 0.5 m Answer 118.77 N Format Check the magnitude of the component parallel to the edge of the door that 218.17 N is perpendicular to the hinge axis, (include units with answer) Format Check Save 25 pts.7 75% 5% try penalty 31.67 pts.95% 5% try penalty Status Tr ● W #tries: ** Tr • W. #tries:
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A Final-163 - S1 1.pdf - Adobe Acrobat Reader DC (32-bit) O X File Edit View Sign Window Help Home Tools Final-163 - S1 1.pdf x Sign In 2 / 5 図。 138% Search 'Crop Page' Export PDF Q.1) For the plate shown in figure, determine the forces in three ropes if the plate weighs 1.6 kN. bE Edit PDF Create PDF Comment Combine Files 1,2 m EI Organize Pages D Compress PDF 0.8 m y B 0.8 m 2 Redact L0.9m 0.9 m C Protect l Fill & Sign 2 Send for Comme. Convert, edit and e-sign PDF forms & agreements Free 7-Day Trial
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9 Com 6NX D (610) Mixic O Micr b Seard O Anh Z Four Z Micr ở writi A Cách ncmute.edu.vn/pluginfile.php/1524373/mod_assign/intro/2122HK2_HWCO3.pdf 22HK2_HWC03 1 / 2 139% + | HOMEWORK OF CHAPTER 3: TRUSS ANALYSIS Question 1 Give a truss as shownin Figure 1. a. Determine the reactions at A and E. b. Determine the force in members AF, GH. 40 kN 80 kN 40 kN H 3 m 3 m 3 m 3 m 3 m Figure 1 DELL
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Question 1) F = 22 kN single load, M = 30 kN.m moment and w = 6 kN/m distributed load affect the beam whose loading condition is given in the figure. Point C is located just to the left of the application point of the force F and the moment M. The length L is given as L this; 4 m. According to w kN/m F kN M kN.m A В C 2L L L L