Required information A resistive load inverter in two logic states is given as follows: Vpp Ipp R R vo = VH o vo = VL I, Ms Ms vj = VL < VTN vi = VH Let VTN = 0.6 V. For the circuit shown in the figure, VL = 0.5 V, VH= 2.6 V, VDD= 2.6 V, Kn = 100 HAV2, VDs = 0.5, VTN=0.6 V and power P= 0.0001 W. Find the new values of R and (W/L)S assuming that the power dissipation remains the same? R= 10500 = 1/ 5

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Required information
A resistive load inverter in two logic states is given as
follows:
DL
DD
IpD
R
vo = VH
ID
o vo = VL
Ms
vj = V < VTN
vj = VH
Let VTN= 0.6 V.
For the circuit shown in the figure, VL = 0.5 V, VH= 2.6 V, VDD= 2.6 V, K =
100 HAV2, Vps = 0.5, VTN=0.6 V and power P= 0.0001 W.
Find the new values of R and (W/L)S assuming that the power dissipation
remains the same?
R= 10500
Ω
(4)s =1|
W
Transcribed Image Text:Required information A resistive load inverter in two logic states is given as follows: DL DD IpD R vo = VH ID o vo = VL Ms vj = V < VTN vj = VH Let VTN= 0.6 V. For the circuit shown in the figure, VL = 0.5 V, VH= 2.6 V, VDD= 2.6 V, K = 100 HAV2, Vps = 0.5, VTN=0.6 V and power P= 0.0001 W. Find the new values of R and (W/L)S assuming that the power dissipation remains the same? R= 10500 Ω (4)s =1| W
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