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Required information A four-cylinder, four-stroke, spark-ignition engine operates on the ideal Otto cycle with a compression ratio of 11 and a total displacement volume of 1.8 L. The air is at 90 kPa and 50°C at the beginning of the compression process. The heat input is 1.1 kJ per cycle per cylinder. The gas constant of air is R = 0.287 kJ/kg-K and use constant specific heats with cv = 0.821 kJ/kg-K, Cp = 1.108 kJ/kg-K, and k = 1.35.

Required information A four-cylinder, four-stroke, spark-ignition engine operates on the ideal Otto cycle with a compression ratio of 11 and a total displacement volume of 1.8 L. The air is at 90 kPa and 50°C at the beginning of the compression process. The heat input is 1.1 kJ per cycle per cylinder. The gas constant of air is R = 0.287 kJ/kg-K and use constant specific heats with cv = 0.821 kJ/kg-K, Cp = 1.108 kJ/kg-K, and k = 1.35.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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What is the max pressure max temperature and mean effective pressure

! Required information A four-cylinder, four-stroke, spark-ignition engine operates on the ideal Otto cycle with a compression ratio of 11 and a total displacement volume of 1.8 L. The air is at 90 kPa and 50°C at the beginning of the compression process. The heat input is 1.1 kJ per cycle per cylinder. The gas constant of air is R = 0.287 kJ/kg-K and use constant specific heats with cv = 0.821 kJ/kg-K, Cp = 1.108 kJ/kg-K, and k=1.35.
Transcribed Image Text:! Required information A four-cylinder, four-stroke, spark-ignition engine operates on the ideal Otto cycle with a compression ratio of 11 and a total displacement volume of 1.8 L. The air is at 90 kPa and 50°C at the beginning of the compression process. The heat input is 1.1 kJ per cycle per cylinder. The gas constant of air is R = 0.287 kJ/kg-K and use constant specific heats with cv = 0.821 kJ/kg-K, Cp = 1.108 kJ/kg-K, and k=1.35.
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