Required information 54 mm 44 mm G Te 46 mm To 40 mm Under normal operating conditions, the electric motor exerts a torque of 2.4 kN-m on shaft AB. Assuming that Tp=1.2
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- -8 Q2: A shaft is driven by a motor which exerts a constant torque while the load taken off the shaft fluctuates from zero to maximum during each revolution. If the maximum fluctuating in energy in one cycle is AE=242 N.m. Find the moment of inertia of the flywheel (I) to be mounted on the shaft so that the speed fluctuating shall not be more than 3 r.p.m. above or below a .mean speed of N=200 r.p.mA horizontal shaft AD supported in bearings at A and B and carrying pulleys at C and D is totransmit 75 kW at 500 r.p.m. from drive pulley D to off-take pulley C, Calculate the diameter of shaft. The data given is : P1 = 2 P2 (both horizontal), Q1 = 2 Q2 (bothvertical), radius of pulley C = 220 mm, radius of pulley D = 160 mm, allowable shear stress = 45 MPa.[Ans. 100 mm] Given CD=350mm CA=100mm AB=150mm BD=100mm3. A motor is connected by a belt to pulley B. T, is the tight-side tensile force equal to 1800 N. The shaft spins at a constant speed, 650 rpm. The power delivered by the motor is 12.6 kW. On pulley A, connected to the load, the slack side of the belt has a tension equal to th of the tight side. b T T, B d shaft Dimensions are as follows: da 200 тm 300 тт | 250 тm |180 тm | 250 тm 26 тm dB dahaft a We analyzed a problem similar to this on Test 01 using static failure theories. Is this strictly correct? Because the shaft is spinning, would not a material particle see a time-varying reversal of the the bending stress as in the R.R. rotating beam test? Would a particle see a reversal of the torsional shear stress? Assume Sut = 370 MPa and Sy = 300 MPa. Ignore Marin factors. Ignore stress concentrations. Ignore direct shear stress (that due to V). Find the safety factors with respect to fatigue and yielding. Be guided by section 6-14 on combined loading.
- Handwritten solution+FBD and explanation.A turbine rotor is mounted on a stepped shaft that is fixed at both ends as shown in The torsional stiffnesses of the two segments of the shaft are given by k = 3,000 N-m/rad and k2 = 4,000 N-m/rad. The turbine generates a harmonic torque given by M(1) = Mo cos wt about the shaft axis with M, = 200 N-m and w = 500 rad/s. The mass moment of inertia of the rotor about the shaft axis is J, = 0.05 kg-m?. Assuming the equivalent torsional damping constant of the system as e, = 2.5 N-m-s/rad, determine the steady-state response of the rotor, 0(1). O(1) M(1) = Mg cos etr %3! Turbine rotor, JoThe shaft shown has two pulleys, where pulley C is the input and pulley A is the output. The shaft is supported by frictionless bearings at points O and B. The pulley diameters are dA = 361 mm and dc = 224 mm. The input tensions on pulley Care T3 = 267 N and T4 = 0.10*T3. The shaft diameter, ds = 25 mm. T₁ da ХОА 1₂ oo ds B dc T3 XAB XBC T₁ • What is the tension T₁ on the output pulley (in N)? Assume the lower tension is 10% of the higher tension.
- Nn.147. Subject :- Mechanical engineeringPlease don't give an incorrect solution. Important problem, Include the FBD.Assuming there is no axial thrust, find the reactions @ A & C. Y Note: Force actlig on gear B is parallel to z-axis. Force acting on year D is parallel to y-ax's. 50 70015 3010 25 in 86916 201 100