Required information 54 mm 44 mm G Te 46 mm To 40 mm Under normal operating conditions, the electric motor exerts a torque of 2.4 kN-m on shaft AB. Assuming that Tp=1.2

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A horizontal shaft AD supported in bearings at A and B and carrying pulleys at C and D is totransmit 75 kW at 500 r.p.m. from drive pulley D to off-take pulley C, Calculate the diameter of shaft. The data given is : P1 = 2 P2 (both horizontal), Q1 = 2 Q2 (bothvertical), radius of pulley C = 220 mm, radius of pulley D = 160 mm, allowable shear stress = 45 MPa.[Ans. 100 mm] Given  CD=350mm CA=100mm AB=150mm BD=100mm

3. A motor is connected by a belt to pulley B. T, is the tight-side tensile force equal to 1800 N. The shaft spins at a constant speed, 650 rpm. The power delivered by the motor is 12.6 kW. On pulley A, connected to the load, the slack side of the belt has a tension equal to th of the tight side. b T T, B d shaft Dimensions are as follows: da 200 тm 300 тт | 250 тm |180 тm | 250 тm 26 тm dB dahaft a We analyzed a problem similar to this on Test 01 using static failure theories. Is this strictly correct? Because the shaft is spinning, would not a material particle see a time-varying reversal of the the bending stress as in the R.R. rotating beam test? Would a particle see a reversal of the torsional shear stress? Assume Sut = 370 MPa and Sy = 300 MPa. Ignore Marin factors. Ignore stress concentrations. Ignore direct shear stress (that due to V). Find the safety factors with respect to fatigue and yielding. Be guided by section 6-14 on combined loading.