Requirea intormation NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part A 52-lb ladder rests against a wall when the bottom begins to slide out. The ladder is 36-ft long and the coefficient of kinetic friction between the ladder and all surfaces is 0.2. Take 0-40°.
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- On route 12 Ash, Misty, and Brock heads to the Fuschia City Safari Zone. However, upon some time, an old man seeks their aid as a Snorlax with a mass of 1014.3 pounds is blocking the road and their village's water supply. If the coefficient of friction is 0.15 find the force needed (in pounds) to push this Pokémon to the left. Include the FBD in your solution with the label of the forces.You have been selected as a potential intern in a construction company in Aqaba, Jordan. For evaluation purposes, you were asked to answer the following question. Two wooden boxes are moving on an inclined surface as shown in Figure 2. Wooden Воx A Non- Frictional Surface Non- Frictional Surface Figure 2: Wooden Boxes Answer the following questions using the D'Alembert's principle. Note that the mass of box A is M1 and the mass of box B is M2. 1. Find the tension in the rope, in terms of M1 and M2. 2. Calculate the acceleration of the wooden boxes, in terms of M1 and M2. Wooden BoxA crate of 68 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.5 m, and the angle 0= 13°. What is the maximum acceleration a (in m/s²) the cart can have without tipping over on the cart? The coefficient of static friction between the crate and the cart is ls = 0.49. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s2. 0.5 m |0.5 m G a Your Answer: Answer
- A crate of 68 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.5 m, and the angle 0= 13°. What is the maximum acceleration a (in m/s²) the cart can have without tipping over on the cart? The coefficient of static friction between the crate and the cart is ls = 0.49. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s². 0.5 m |0.5 m • G a Your Answer: AnswerA 68 kg credenza is being pushed to move it. Due to use of sliders on the right side "feet," the coefficient of static friction at those feet, labeled B, is .2 while the coefficient of static friction at the feet labeled A is .4. Assuming impending motion, find the minimum force needed to move the credenza. Draw a clear and complete FBD before setting up your equations. Make sure your equations are clear before solving them! 0.8 m 0.7 m 0.6 m 0.6 m1. A force of 69N is needed to start an 6.9kg box moving across a horizontal surface. Calculate the coefficient of static friction. If the box continues to move with an acceleration of 1.69 m/s2. What is the coefficient of kinetic friction? 2. A box of 450N is lying in an inclined plane with angle of 35 degrees. If the applied load to move the box is 269N. Determine the net Ff and the acceleration of the box if the coefficient of static friction is 0.35 and the coefficient of kinetic friction is 0.28.
- A 2-t mass rests on a horizontal surface. Calculate the horizontal force, in kilonewtons, required to move this mass at a uniform speed along the surface if the coefficient of friction is 0-35.You have been selected as a potential intern in a construction company in Aqaba, Jordan. For evaluation purposes, you were asked to answer the following question. Two wooden boxes are moving on an inclined surface as shown in Figure 2. Wooden Box A Non- Frictional Surface Non- Frictional Surface 60 Figure 2: Wooden Baxes Answer the following questions using the D'Alembert's principle. Note that the mass of box A is M1 and the mass of box B is M2. Wooden BoxA dictionary is pulled to the right at constant velocity by a 10 N force acting 30° upward above the horizontal. The coefficient of kinetic friction between the book and the horizontal surface is 0.5. What is the weight of the book?
- Q5 A pull of 20 N at 30 ° to the horizontal is necessary to move a block of wood on a horizontal table . If the coefficient of friction between the bodies in contact is 0.25 , what is the weight of the block ?pls send me answer of this question all the parts pls and i will rate you sure, pls solve a,b,c and d and also a and b A 200-kg dragster (racing car) exerts a constant force of 4000 N during a race. The coefficient of kinetic friction between the tires and the pavement is .15. If the drag strip is 1000 m long, determine:a. The net force on the dragster. b. The acceleration of the dragster. c. The time it takes for the dragster to finish the race.d. The dragster's velocity at the end of the race.The dragster now needs to slow down, so it opens a parachute. The force of air drag is 3500 N. The driver also locks the brakes of the dragster, and the coefficient of kinetic friction becomes .75. Determine:a. How long it will take to stop the dragster.b. The distance the dragster travels while stopping.Required information A photograph of the NASA Apollo 16 Lunar Module (abbreviated by NASA as the LM) is shown on the surface of the Moon. Such spacecraft made six Moon landings during 1969 - 72. A simplified model for one of the four landing gear assemblies of the LM is shown. Assume the weight of the LM is uniformly supported by all four landing gear assemblies, and neglect friction between the landing gear and the surface of the Moon. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A (2.5, 2.5, -2.2) m B (1.5, 1.5,0) m C(2, 1,-1.2) m D(1,2,-1.2) m Z B D If the LM has 14950 kg mass and rests on the surface of the Moon where acceleration due to gravity is 1.62 m/s2, determine the forces supported by members AB, AC, and AD. (Round the final answers to four decimal places. Include a minus sign if necessary.) The forces supported by members AB, AC, and AD are as follows: TAB 10621 N TAC= 2903 N TAD 6032 N