Replace the loading on the beam by an equivalent resultant force and specify its location measure from point A. 2.5 kN/m A 3 m 0.5 kN/m OB 1 m 1.5 kN

Calculate the magnitude of the resultant for the force system shown in figure below. 600N SOON 407 30' 400N 300N

Determine the direction delta of the resultant force acting on the corble measured couterclockwise from the x axi FR= -1790 lb

Consider the pipe structure projecting from the wall at point “A”. Find the resultant force and couple moment acting at point “A”.   Express the resultant force and couple moment in Cartesian (vector) form.  (Hint: the 1,000 lb force needs to be expressed as a vector and the “dimension box” provides the information necessary to define the unit vector in the direction of F.)

Determine the resultant R of the system of distributed loads and locate its line of action with respect to the left support for y 400 Ib/ft 300 Ib/ft 150 Ib/ft A 7 ft 8 ft

Answer neatly with a complete solution

the non-homogeneous equation y” – 2y’ = t + dt, then determine this solution

Determine graphically the magnitude and direction of their resultant when P = 200 lbs and Q = 380 lbs with a = -45* and B = -115*. %3D -45° 25° 45° -115° 380lb 200lb