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Removex() routine deletes all nodes whose info field contains the value x. void removex(NODEPTR *head , int x) { NODEPTR p, q , save; int y; q=NULL; p=*head; while (p!=NULL) if (p->info == x) {save=p; p= p->next; if (q==NULL) { freenode(*head); *head = p; else {freenode(save); q->next=p;} }else :d = b} p= p->next; }

Removex() routine deletes all nodes whose info field contains the value x. void removex(NODEPTR *head , int x) { NODEPTR p, q , save; int y; q=NULL; p=*head; while (p!=NULL) if (p->info == x) {save=p; p= p->next; if (q==NULL) { freenode(*head); *head = p; else {freenode(save); q->next=p;} }else :d = b} p= p->next; }

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
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This code deletes all nodes whose info field contains the value x.

Please modify the code to delete the only first value of x : 

( with explanation for each line if possible) many thanks.

( do not care about yellow )

 

Removex() routine deletes all nodes whose info field contains the value x. void removex(NODEPTR *head , int x) { NODEPTR p , q , save; int y; q=NULL; p=*head; while (p!=NULL) if (p->info == x) {save=p; p= p->next; if (q==NULL) { freenode(*head); *head = p; else {freenode(save); q->next=p;} }else {q = p; p=p->next; } }
Transcribed Image Text:Removex() routine deletes all nodes whose info field contains the value x. void removex(NODEPTR *head , int x) { NODEPTR p , q , save; int y; q=NULL; p=*head; while (p!=NULL) if (p->info == x) {save=p; p= p->next; if (q==NULL) { freenode(*head); *head = p; else {freenode(save); q->next=p;} }else {q = p; p=p->next; } }
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