Relax! A recent survey asked  1678  people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 112 1 185 2 337 3 254 4 318 5 230 6 150 7 30 8 62 Total 1678 Send data to Excel Consider these 1678 people to be a population. Let  X  be the number of hours of relaxation for a person sampled at random from this population.   Part 1 of 5     (a) Construct the probability distribution of  X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) .067 .110 .200 .151 .190 .137 .090 .018 .037       Part 2 of 5     (b) Find the probability that a person relaxes more than  6  hours per day. The probability that a person relaxes more than  6  hours per day is  .04 .( Round the answer to three decimal places.)       Part 3 of 5     (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is  0 .( Round the answer to three decimal places.)       Part 4 of 5     (d) Compute the mean  μx . Round the answer to two decimal places. μx   =           Part 5 of 5     (e) Compute the standard deviation  σx . Round the answer to three decimal places.

Part 2 Let x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional baseball player. A random sample of n = 6 professional baseball players gave the following information. x 0.338 0.306 0.340 0.248 0.367 0.269 y 3.5 7.7 4.0 8.6 3.1 11.1  Σx = 1.868, Σy = 38, Σx2 = 0.592034, Σy2 = 294.32, Σxy = 11.1556, and r ≈ -0.901. Se ≈ 1.5890, a ≈ 26.420, and b ≈ -64.517. (a) Find the predicted percentage  of strikeouts for a player with an x = 0.328 batting average. (Use 2 decimal places.) %(b) Find a 90% confidence interval for y when x = 0.328. (Use 2 decimal places.) lower limit  % upper limit  %

Relax! A recent survey asked  1682  people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 113 1 184 2 336 3 251 4 318 5 234 6 151 7 35 8 60 Total 1682 Send data to Excel Consider these 1682 people to be a population. Let  X  be the number of hours of relaxation for a person sampled at random from this population.   Part 1 of 5     (a) Construct the probability distribution of  X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x )                         Part 2 of 5     (b) Find the probability that a person relaxes more than  4  hours per day. The probability that a person relaxes more than  4  hours per day is…

The data given below show the number of overtime hours worked in one week per employee. Use the data to complete parts​ (a) and​ (b).   Overtime hours 0 1 2 3 4 5 6   Employees 4 14 25 54 44 28 18     ​(a) Construct a probability distribution. ​(b) Graph the probability distribution using a histogram and describe its shape.       ​(a) Construct the probability distribution by completing the table below.   x 0 1 2 3 4 5 6 ​P(x) enter your response here enter your response here enter your response here enter your response here enter your response here enter your response here enter your response here   ​(Round to three decimal places as​ needed.) ​(b) Choose the correct graph of the probability distribution.     A.                   012345600.10.20.30.4Overtime HoursProbability         A histogram has a horizontal axis labeled Overtime Hours from 0 to 6 in increments of 1…

The data given below show the number of overtime hours worked in one week per employee. Use the data to complete parts​ (a) and​ (b).   Overtime hours 0 1 2 3 4 5 6   Employees 4 14 35 53 46 26 17     ​(a) Construct a probability distribution. ​(b) Graph the probability distribution using a histogram and describe its shape. ​(a) Construct the probability distribution by completing the table below.   x 0 1 2 3 4 5 6 ​P(x) nothing nothing nothing nothing nothing nothing nothing   ​(Round to three decimal places as​ needed.)

Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population. Time(Months) Number of Articles 0-0.9 48 1.0-1.9 18 2.0-2.9 15 3.0-3.9 20 4.0-4.9 10 5.0-5.9 13 (a) Approximate the variance of the times. Round the answer to at least two decimal places. The variance is (b) Approximate the standard deviation of the times. Round the answer to at least two decimal places.The standard deviation is   Can you please help me with question a & b?  A) variance b) standard deviation

part C D E

The normal distribution curve can be used as a probability distribution curve for normally distributed variables. Group of answer choices False True

The table shows population statistics for the ages of Best Actor and Best Supporting Actor winners at an awards ceremony The distributions of the ages are approximately bell-shaped. Compare the z-scores for the actors in the following situation. Best Actor Best Supporting Actor H= 51.0 H = 43.0 6 = 6.9 0 = 16 In a particular year, the Best Actor was 50 years old and the Best Supporting Actor was 47 years old. Determine the z-scores for each. Best Actor: z = Best Supporting Actor: z = (Round to two decimal places as needed.) Clear All Check Answer Help Me Solve This View an Example Get More Help - 10:22 PM P Type here to search 68°F Cloudy ^ 24 88 10/7/2021 10.0517 Esc FI C F5 F2 F3 F4 F6 F7 F8 PrtSc Insert Delete F9 F10 F11 F12 C@ 3 6 80 Backspace Num Lock T Y U P 7 Home PaUp S D G +II HI 5 LL LU