Relax! A recent survey asked 1678 people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 112 1 185 2 337 3 254 4 318 5 230 6 150 7 30 8 62 Total 1678 Send data to Excel Consider these 1678 people to be a population. Let X be the number of hours of relaxation for a person sampled at random from this population. Part 1 of 5 (a) Construct the probability distribution of X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) .067 .110 .200 .151 .190 .137 .090 .018 .037 Part 2 of 5 (b) Find the probability that a person relaxes more than 6 hours per day. The probability that a person relaxes more than 6 hours per day is .04 .( Round the answer to three decimal places.) Part 3 of 5 (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is 0 .( Round the answer to three decimal places.) Part 4 of 5 (d) Compute the mean μx . Round the answer to two decimal places. μx = Part 5 of 5 (e) Compute the standard deviation σx . Round the answer to three decimal places.
Relax! A recent survey asked 1678 people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 112 1 185 2 337 3 254 4 318 5 230 6 150 7 30 8 62 Total 1678 Send data to Excel Consider these 1678 people to be a population. Let X be the number of hours of relaxation for a person sampled at random from this population. Part 1 of 5 (a) Construct the probability distribution of X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) .067 .110 .200 .151 .190 .137 .090 .018 .037 Part 2 of 5 (b) Find the probability that a person relaxes more than 6 hours per day. The probability that a person relaxes more than 6 hours per day is .04 .( Round the answer to three decimal places.) Part 3 of 5 (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is 0 .( Round the answer to three decimal places.) Part 4 of 5 (d) Compute the mean μx . Round the answer to two decimal places. μx = Part 5 of 5 (e) Compute the standard deviation σx . Round the answer to three decimal places.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter7: Integration
Section7.CR: Chapter 7 Review
Problem 88CR
Related questions
Question
Relax! A recent survey asked
1678
people how many hours per day they were able to relax. The results are presented in the following table.
| Number of Hours | Frequency |
|
0
|
112
|
|
1
|
185
|
|
2
|
337
|
|
3
|
254
|
|
4
|
318
|
|
5
|
230
|
|
6
|
150
|
|
7
|
30
|
|
8
|
62
|
| Total |
1678
|
Send data to Excel
Consider these 1678 people to be a population. Let
X
be the number of hours of relaxation for a person sampled at random from this population.
Part 1 of 5
(a) Construct the probability distribution of
. Round the answer to three decimal places.
X
|
|
Part 2 of 5
(b) Find the probability that a person relaxes more than
hours per day.
6
|
The probability that a person relaxes more than
6
.04
|
|
Part 3 of 5
(c) Find the probability that a person doesn't relax at all.
|
The probability that a person doesn't relax at all is
0
|
|
Part 4 of 5
(d) Compute the mean
. Round the answer to two decimal places.
μx
|
μx
=
|
|
Part 5 of 5
(e) Compute the standard deviation
. Round the answer to three decimal places.
σx
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