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Relax! A recent survey asked  1678  people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 112 1 185 2 337 3 254 4 318 5 230 6 150 7 30 8 62 Total 1678 Send data to Excel Consider these 1678 people to be a population. Let  X  be the number of hours of relaxation for a person sampled at random from this population.   Part 1 of 5     (a) Construct the probability distribution of  X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) .067 .110 .200 .151 .190 .137 .090 .018 .037       Part 2 of 5     (b) Find the probability that a person relaxes more than  6  hours per day. The probability that a person relaxes more than  6  hours per day is  .04 .( Round the answer to three decimal places.)       Part 3 of 5     (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is  0 .( Round the answer to three decimal places.)       Part 4 of 5     (d) Compute the mean  μx . Round the answer to two decimal places. μx   =           Part 5 of 5     (e) Compute the standard deviation  σx . Round the answer to three decimal places.

Relax! A recent survey asked  1678  people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 112 1 185 2 337 3 254 4 318 5 230 6 150 7 30 8 62 Total 1678 Send data to Excel Consider these 1678 people to be a population. Let  X  be the number of hours of relaxation for a person sampled at random from this population.   Part 1 of 5     (a) Construct the probability distribution of  X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) .067 .110 .200 .151 .190 .137 .090 .018 .037       Part 2 of 5     (b) Find the probability that a person relaxes more than  6  hours per day. The probability that a person relaxes more than  6  hours per day is  .04 .( Round the answer to three decimal places.)       Part 3 of 5     (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is  0 .( Round the answer to three decimal places.)       Part 4 of 5     (d) Compute the mean  μx . Round the answer to two decimal places. μx   =           Part 5 of 5     (e) Compute the standard deviation  σx . Round the answer to three decimal places.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

Relax! A recent survey asked 

1678

 people how many hours per day they were able to relax. The results are presented in the following table.

Number of Hours Frequency
0
112
1
185
2
337
3
254
4
318
5
230
6
150
7
30
8
62
Total
1678

Send data to Excel

Consider these 1678 people to be a population. Let 

X

 be the number of hours of relaxation for a person sampled at random from this population.

 

Part 1 of 5
 
 
(a) Construct the probability distribution of 
X
. Round the answer to three decimal places.
x
0
1
2
3
4
5
6
7
8
P
(
x
)
.067
.110
.200
.151
.190
.137
.090
.018
.037
 
 
 
Part 2 of 5
 
 
(b) Find the probability that a person relaxes more than 
6
 hours per day.

The probability that a person relaxes more than 
6
 hours per day is 
.04
.( Round the answer to three decimal places.)
 
 
 
Part 3 of 5
 
 
(c) Find the probability that a person doesn't relax at all.

The probability that a person doesn't relax at all is 
0
.( Round the answer to three decimal places.)
 
 
 
Part 4 of 5
 
 
(d) Compute the mean 
μx
. Round the answer to two decimal places.

μx
 
=
 
 
 
 
 
Part 5 of 5
 
 
(e) Compute the standard deviation 
σx
. Round the answer to three decimal places.
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