Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Relative Motion Analysis using Rotating Axes, use the formulas attached to find the solution to the problem, in addition you can use Relative motion using translating axes to find velocity and acceleration of D and E, but to find the velocity of C you must use the rotating axis formula given, the formula given is a general formula. State which where the axis XYZ and xyz will be. Solve in vector form.

The mechanism shown consists of rigid members AB, BC, DE, and EF, which
are pinned at A, B, D, E, and F. End C of member BC is pinned to a block which
slides on member DE. For the given position, @AB = 2 rad per sec clockwise and
αAB = 3 rad per sec² counterclockwise. Determine the velocity and acceleration of
the block at C for this position.
3'
4'
D
B
A
4'
C
4'
E
4
3
5'
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Transcribed Image Text:The mechanism shown consists of rigid members AB, BC, DE, and EF, which are pinned at A, B, D, E, and F. End C of member BC is pinned to a block which slides on member DE. For the given position, @AB = 2 rad per sec clockwise and αAB = 3 rad per sec² counterclockwise. Determine the velocity and acceleration of the block at C for this position. 3' 4' D B A 4' C 4' E 4 3 5'
Acceleration
a³ = a₁ + ²X PB/A + ²x (@XFBA) +25ZX (VBIA) +
ag = acceleration of B, measured from the X, Y, Z reference
aA = acceleration of A, measured from the x, y, z reference
(aB/A)xyz, (VB/A)xyz = acceleration and velocity of B with respect to A,
as mesaured by an observer attached to the rotating x,y,z reference.
, angular acceleration and angular velocity of the x, y, z reference
measured from X, Y, Z.
TB/A= position of B with respect to A
Acceleration
Taking time derivative
dve
st
18
"
(V8/A)x+z
VB
√B = VA + SEX √B/A + (US/A)XNz
(AB/A) 2
dva +dexroa + exdrea +
-XrB/A
at
dt
dt
+ex PBA+
drBia
dt
+
d(√BIA) XYZ
at
d (√5 /A) XYZ
dt
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Transcribed Image Text:Acceleration a³ = a₁ + ²X PB/A + ²x (@XFBA) +25ZX (VBIA) + ag = acceleration of B, measured from the X, Y, Z reference aA = acceleration of A, measured from the x, y, z reference (aB/A)xyz, (VB/A)xyz = acceleration and velocity of B with respect to A, as mesaured by an observer attached to the rotating x,y,z reference. , angular acceleration and angular velocity of the x, y, z reference measured from X, Y, Z. TB/A= position of B with respect to A Acceleration Taking time derivative dve st 18 " (V8/A)x+z VB √B = VA + SEX √B/A + (US/A)XNz (AB/A) 2 dva +dexroa + exdrea + -XrB/A at dt dt +ex PBA+ drBia dt + d(√BIA) XYZ at d (√5 /A) XYZ dt
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Follow-up Question

Velocity of C relative to D isn't 0 since block C slides along member DE, while member DE rotates, and you didn't use the formula for rotating axis

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Follow-up Question

Velocity of C relative to D isn't 0 since block C slides along member DE, while member DE rotates, and you didn't use the formula for rotating axis

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