Refer to page 15 for a problem involving evaluating a double integral in polar coordinates. Instructions: Convert the given Cartesian integral to polar coordinates. Show all transformations and step-by-step calculations. Link [https://drive.google.com/file/d/1wKSrun-GlxirS31Z9qoHazb9tC440AZF/view?usp=sharing]

Use inplicit differentiation and convert to polar. See images

Convert to polar coordinates where r>0 and 0 <0 < 27T. (0, 3) O LLATEX: \left(2,\:\frac{5\pi}{6}\right) O (1, #} O (3. 5) OLLA TeX: \left(4,\:\pi\right)

Convert the equation rsin 0 = lnr + ln cos 0 from polar to cartesian.

Change to polar then evaluate -2 cV2x-x2 (x² + y²) dydx

If you can only answer one question, please answer 128. How do you convert from parametric to polar equations in this case? The answer is sqrt(2)*cos(theta+pi/4) all over sin(2theta)+1 but am not sure how to get the answer. *Please make sure the formatting is readable!