The Ahmadi Corporation wants to increase the productivity of its line workers. Four differentprograms have been suggested to help increase productivity. Twenty employees, making up asample, have been randomly assigned to one of the four programs and their output for a day's workhas been recorded. You are given the results below. At 95% confidence, conduct the ANOVA testto determine whether there is a significant difference in the mean output under the four programs.Program AProgram BProgram CProgram D150150185175130120120135180160145110Part of the ANOVA table is shown below.Source of Variation Sum of Squares8,750Between GroupsWithin Groups16,350Total220190180175d.f.19150120130175Mean Square Refer to Exhibit 1. The mean square error isO 475860.532916.67O8750

Answered: Image /qna-images/answer/cd1bf0b5-320a-4545-b617-1b6e164192eb.jpg

Answered: Refer to Exhibit 1. The mean square…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0150. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.) Enter your answer in the answer box.
The number of bpms (bits per microseconds) passed through a gate is given below. Find the median bpms. 70 60 50 61 78 32 73 28 39 19 63
The specification limits for a product are 8 cm and 10 cm. A process that produces the product has a mean of 8.5 cm and a standard ?deviation of 0.2 cm. What is the process capability, Cpk .a 1.67 .b 3.33 .C None of them .d 0.83 .e 2.50
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.1047. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.)
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.7673. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.)
Calculate the standard deviation of 2,3,3,3,9.
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.8962. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. =(Type an integer or decimal rounded to three decimal places as needed.)
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9616. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.) - X - X Standard normal table (page 1) Standard normal table (page 2) - 3.3 .0004 0005 .0003 .0004 .0004 .0004 .0004 .0004 .0005 .0005 .0005 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 - 3.2 .0005 .0005 .0006 .0006 .0006 .0006 .0006 .0007 .0007 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 3.1 .0007 .0007 .0008 .0008 .0008 .0008 .0009 .0009 .0009 .0010 0.4 .6554 .6591 .6628 .6700 .6736 .6772 .6808 .6844 .6879 .6664 - 3.0 – 2.9 .0010 .0010 .0011 .0011 .0011 .0012 .0012 .0013 .0013 .0013 .6915 .7019 .7088 .7422…
Need help. Will give thumbs up! Data typed below. Thank you! TSERofReturn AcmeRofReturn -1.99167 -1.03712 2.64815 3.04528 -0.58856 0.44802 -0.76395 0.60781 -0.81178 2.51735 -0.14212 1.70972 0.17677 -0.27609 0.54349 1.18672 -0.09428 0.49632 0.3681 -3.08347 0.60727 1.4182 1.3726 0.1878 -0.8915 -1.81699 1.8031 0.975 -0.26967 1.85853 2.42493 2.33005 -0.95528 -0.48742 -0.28562 -0.15591 -2.13517 -1.67924 -0.85961 1.57905 1.0856 -4.09194 -1.06689 -0.43368 0.04922 1.22281 3.2381 -0.55675 1.05371 -0.23124 -1.1785 -5.10525 1.11749 0.5909 -0.01456 1.70857 1.13344 0.93883 2.6641 0.92507 -1.33795 0.9294 -1.65683 -1.93668 -2.21489 -5.10648 -1.19445 0.47456 -0.461 0.19373 0.6551 -0.44915 1.5161 -1.11084 3.42943 2.58471 -0.3175 1.17337 -0.47695 -1.08238…
In one of the Stat 2 sections, the students in the section have an average height of 64 inches, with a standard deviation of 3 inches. The GSI happens to be 68 inches. Express the height of the GSI in standard units, relative to the students in the section. Choose the answer below that is closest. Group of answer choices 1.67 3.0 1.5 1.33 4.0 PreviousNext
List the standard deviations in ascending order.In which measurement is the standard deviation greater?*2000 ±20, *122 ± 2,*188±7
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0129. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decipaall eaundad to thcee deeisel elese apeaded - X Standard normal table (page 2) Standard normal table (page 1) Standard Normal Distribution Standard Normal Distribution Critical Values Critical Values Level of Confidence c Level of Confidence c 0.80 1.28 0.80 1.28 0.90 1.645 Area 0.90 1.645 0.95 1.96 0.95 1.96 0.99 2.575 0.99 2.575 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .09 .08 .07 .06 05 .04 .03 .02 .01 .00 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 - 3.4 - 3.3 - 3.2 - 3.1 - 3.0 - 2.9 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0.1 .5398 .5438 .5478 .5517…

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Refer to Exhibit 1. The mean square error is O 475 860.53 2916.67 O8750