Reagents A. Cu(SO4)2, NaHCO3, Na-citrate B. concentrated HCI, orcinol, FeCl3 C. Alkyl chloride, AlCl3 D. NH₂OH, alcoholic HCl, alcoholic KOH, FeCl3 E. Dilute KMnO4 F. NaOH, KI, 1₂ G. FeCl3 Observation H. blue-green solution 1. Formation of purple-colored solution J. Decolorization of purple solution and formation of brown precipitate K. Formation of yellow precipitate L. Formation of a colored complex M. Appearance of a brick red precipitate N. Change in color of the crystal; warm test tube Given the following reagents and tests above, what could best differentiate the two compounds below? Provide also the letter of the expected experimental observation and state which of the two would give that result.

A buffered solution containing dissolved aniline, C,H,NH,, and aniline hydrochloride, C,H,NH;CI, has a pH of 5.50. A. Determine the concentration of C,H,NH in the solution if the concentration of C,H,NH, is 0.305 M. The pKp of aniline is 9.13. [C,H,NH ] = 0.0715 M B. Calculate the change in pH of the solution, ApH, if 0.374 g NaOH is added to the buffer for a final volume of 1.05 L. Assume that any contribution of NaOH to the volume is negligible. 4.33 ApH Incorrect

Choose the answer that best represents the products of the following reaction.   Potassium carbonate is reacted with phosphoric acid.      A.  2  K3PO4 (aq)        +        3  H2O (l)        +      3  CO2 (g)  B.  K2CO3         +       H3PO4         C.  3  K2CO3         +       2  H3PO4         D.  2  K3PO4 (aq)        +        3  H2CO3 (aq)

What is the fluoride ion concentration for a saturated solution of SrF2 if the Ksp for SrF2 is 2.5 x 10-9?   a. 6.3 × 10-26 M   b. 1.7 × 10-3 M   c. 8.5 × 10-4 M   d. 3.4 × 10-4 M

Without doing any calculations (just compare the correct Ksp values) complete the following statements: 1. magnesium fluoride is MORE soluble than A 2. magnesium fluoride is LESS soluble than B A. PbBr2 B. Ni(CN)2 C. COCO3 D. COS

If the Kc for the following reaction A is 5.0 at what is the Kc for reaction B?Show work.A. Cl2 (g) + CO (g) ↔ COCl2 (g)B. 3 COCl2 (g) ↔ 3 Cl2 (g) + 3 CO (g

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