Read the problem below and answer the following questions. 1) What statistical test should be used to solve this problem? 2) State the null and alternative hypotheses for the test. Bicep strength (kg/cm2) was measured in 2 groups of 12 males each (age=18-25). One group received a hormone injection (H) and the other did not (NH). Is mean bicep strength greater in the group receiving the hormone injection?

The mean potassium content of a popular sports drink is listed as 132 mg in a 32-oz bottle. Analysis of 24 bottles indicates a sample mean of 131.2 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.. a. Ho: μ= 132 mg vs. H₁: b. He: ≤132 mg vs. H₁: c. He: ≥132 mg vs. H₁: Oa Ob Oc (b) Assuming a known standard deviation of 2.1 mg, calculate the z test statistic to test the manufacturer's claim. (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.) Test statistic 132 mg >132 mg <132 mg (c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim? Decision Rule: Reject Ho

Use the following R output to answer the question.   Use the following R output to answer the question. >chisq.test(data) Pearsons Chi-square test data:data X-squared=4.7194, df=2, p-value=0.09445 If the significance level is 5%, what conclusion can you make? Group of answer choices A. fail to reject the alternative hypothesis B. cannot determine C. fail to reject the null hypothesis D. reject the null hypothesis and accept the alternative hypothesis

Is the mean length of adult invasive Lionfish in the Atlantic coast of South Carolina greater than 355.6mm? (don't answer this, this is just so you know what the data is for) Answer the following questions and use the provided excel images, data on the far left is lionfish data Question 2. Describe your null and alternative hypotheses using symbols. Question 3. Select the significance level (a). Question 4. Select an appropriate test, calculate the test statistic and p-value using Excel. Question 5. Determine whether you should reject or not reject the null hypothesis based on the p-value. State the reason to support your answer. Question 6. Describe your conclusion in words in the context of your research question. paste data below Use this sheet to perform a 1-sample t-test. 457.2 431.9 COUNT MEAN 20.00 437.45 438.2 STANDARD DEVIATION 16.48 436.4 STANDARD ERROR 3.69 416.8 454.6 Confidence Interval 95% 456.6 Level of Significance 0.05 453.1 404.9 447.9 437.9 HYPOTHESIS TEST t-VALUE…

You may need to use the appropriate technology to answer this question. Submitted The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A B C P 20 44 50 Q 30 26 30 Test for independence of the row and column variables using a = 0.05. State the null and alternative hypotheses. Ho: The column variable is independent of the row variable. H: The column variable is not independent of the row variable. Ho: Variable P is not independent of variable Q. H: Variable P is independent of variable Q. Ho: Variable P is independent of variable Q. H: Variable P is not independent of variable Q. : The column variable is not independent of the row variable. Ho: : The column variable is independent of the row variable. Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value %3D State your conclusion. Reject Ho. We conclude that the column and row variables are…

An article reports that men over 6 feet tall earn more than men under 6 feet, with these numbers: average 6 foot plus male’s salary $55,000, average male’s salary under 6 foot tall of $47,000, with a p-value of 0.45. Based on that reported p-value, and using the common definition of "statistical significance," which is the case?   With that p value, the results are not significant.    With that p value, the differences are very close, but not statistically significant.   The salary differences are not statistically significant.   The salary differences are statistically significant.

In a random sample of​ males, it was found that 27 write with their left hands and 210 do not. In a random sample of​ females, it was found that 55 write with their left hands and 454 do not. Use a 0.05 significance level to test the claim that the rate of​ left-handedness among males is less than that among females. Complete parts​ (a) through​ (c) below.       Question content area bottom Part 1 a. Test the claim using a hypothesis test.   Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis​ test?     A. H0​: p1=p2 H1​: p1>p2   B. H0​: p1≥p2 H1​: p1≠p2   C. H0​: p1≠p2 H1​: p1=p2   D. H0​: p1=p2 H1​: p1≠p2   E. H0​: p1=p2 H1​: p1<p2   F. H0​: p1≤p2 H1​: p1≠p2 Part 2 Identify the test statistic.   z=enter your response here ​(Round to two decimal places as​ needed.) Part 3 Identify the​ P-value.…

Please sir or ma’am, please help me with hypothesis, critical region, and t statistic.

Identify the IV and the scale of measurement;  Identify the DV and the scale of measurement and for the IV – identify the number of levels; Identify null and alternative hypotheses, are they directional or non-directional?   Assume that the distributions of the populations are approximately normal.

Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left arm 143 179 OA. Ho: H0 H₁: Hd=0 OC. Ho: P = 0 H₁: Hd 0 sufficient evidence to support the claim of a difference in measurements between the two arms.