Read integers from input and store each integer into a vector until -1 is read. Do not store -1 into the vector. Then, output the values in the vector that are less than the last value in the vector, each on a new line. Ex: If the input is 26 -98 -39 -14 -1, the output is: -98 -39
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Read integers from input and store each integer into a
Ex: If the input is 26 -98 -39 -14 -1, the output is:
-98 -39
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- Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements in the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2 != 0) returns true if x is odd. int value; int i; bool isodd; 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 } cin >> value; while (value != 0) { } for (i = 0; i > value; Check return 0; 1 Next level 2 X 1: Compare output 3 4 For input -9 12 -6 1 0, the vector elements are -9, 12, -6, and 1. The last element, 1, is odd. The odd elements in the vector, -9 and 1, are output, each on a new line. Not all tests passed. 2 V 3Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements in the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2!= 0) returns true if x is odd. 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20} vector vect1; int value; int i; bool isodd; cin >> value; while (value != 0) { vect1.push_back(value); cin >> value; } V* Your code goes here */ return 0; 2 3Integer numInputs is read from input. Given the integer vector hourlyScores with the size of numInputs, write a for loop to output the integers in the second half of hourlyScores in reverse order. Separate the integers with a vertical bar surrounded by spaces ("I Ex: If the input is 8 86 88 97 116 132 146 148 163 then the output is: 163 | 148 | 146 | 132 Note: The vector size is always even. int i; int numInputs; 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23} cin >> numInputs; // Creates a vector of size numInputs and initialize all values to 0 hourlyScores.resize(numInputs); for (i = 0; i > hourlyScores.at(i); } * Your code goes here */ cout << endl; return 0;
- Write the following function #input: a numerical vector x #output:the normalized vector, i.e. the vector rescaled into [0,1] # the formula to normalize is (x-min(x))/ (max(x)-min(x)) # you can NOT use the functions min and max # you can use %%, nrow, ncol, and length # you can write multiple functionsIn C++ please: Read integers from input and store each integer into a vector until 0 is read. Do not store 0 into the vector. Then, output all values in the vector (including the last value) each multiplied by the last value in the vector. Output each value on a new line. Ex: If the input is -63 79 -48 7 0, the output is: -441 553 -336 49 #include <iostream>#include <vector>using namespace std; int main() { //place code herereturn 0;}Define an integer vector and ask the user to give you values for the vector. because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). then
- Integer numin is read from input. Given the integer vector yearlySalary with the size of numin, write a for loop to initialize the first half of yearlySalary with the remaining integers read from input. Ex: If the input is 6 116 132 134 then the output is: 116 132 134 0 0 0 Note: The vector size is always even. 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21} vector yearlySalary; unsigned int i; int numIn; cin >> numIn; // Creates a vector of size numIn and initialize all values to 0 yearlySalary.resize(numIn); /* Your code goes here */ for (i = 0; i < yearlySalary.size(); ++i) { cout << yearlySalary.at (i) << " "; } return 0;Vector Arithmetics M A function named arithGym requires an input variable h, and returns three outputs: (1) column vector u, column vector z. and scalar variable count. The input variable h is a column vector of random numbers with values between 100 and 100. The length of h is also randomly chosen between 30 and 60 elements. Perform the following operations. 1. Calculate u with the same length as h that has evenly spaced values ranging from the minimum value in h to the maximum value in h. 2. Each element of column vector z is equal to the square of the corresponding element in h divided by 2 times the corresponding element in u 3. Compute the scalar variable count that counts the number of instances an element in z has a value less than the value of the corresponding element in h. Make sure to assign the results to the output variables as indicated Solve this problem using only vectorized code with no loops or if statements. Note the variable h is defined as a function input. Do not…# phyton A vector contains the grades obtained by students of a class in an assessment, with the following characteristics: Notes are actual values between zero and ten.If the value is equal to -1.0, then this means that the student has missed the assessment.The average approval rate at this University is 6 (six).Write a program that reads two vectors: the note vector described and a vector containing the students' names of the same size. As an output, print the following information in the console in this order: How many students missed the evaluation?How many students have been approved?Among the students present, how many students failed?Among the students present, what was the average grade, with up to two decimal places of accuracy?What's the name of the student who got the highest grade in the class?TipsCreate different counters to find the value of outputs 1 through 4. These counters are different from the loop counter that traverses the vector;Within the while loop, use five…
- (1) Prompt the user to input five pairs of numbers: A player's jersey number (0 - 99) and the player's rating (1 - 9). Store the jersey numbers in one int vector and the ratings in another int vector. Output these vectors (i.e., output the roster). Ex: Enter player 1's jersey number: 84 Enter player 1's rating: 7 Enter player 2's jersey number: 23 Enter player 2's rating: 4 Enter player 3's jersey number: 4 Enter player 3's rating: 5 Enter player 4's jersey number: 30 Enter player 4's rating: 2 Enter player 5's jersey number: 66 Enter player 5's rating: 9 ROSTER Player 1 -- Jersey number: 84, Rating: 7 Player 2 -- Jersey number: 23, Rating: 4 ... (2) Implement a menu of options for a user to modify the roster. Each option is represented by a single character. Following the initial 5 players' input and roster output, the program outputs the menu. The program should also output the menu again after a user chooses an option. The program ends when the user chooses the option to Quit. For…3. Use two vectors and make them into one. Use the following vectors:Vector#1 {1, 1, 5, -3, 0}Vector#2 {9,7,2}Return a vector containing 1, 1, 5, -3, 0, 9, 7, 2 (in that order)a vector can be either a row vector or a .column vector no O yes cannot say O can be yes or no O