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Re write again text form not handwriting. Also need substitutions please do it. Both Physics expert

Re write again text form not handwriting. Also need substitutions please do it. Both Physics expert

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Re write again text form not handwriting. Also need substitutions please do it. Both Physics expert
F 1-7 Required :- Electric field intensity, E= ? Criven, Force, F = 5N Change, 9 = 6×10 6 c Formula used, E = F/8 Now, E = F 5. 6×106 05 E = 8.33×105 N/C Hence, the required electric field ins 8.33× 105 N/C
Transcribed Image Text:F 1-7 Required :- Electric field intensity, E= ? Criven, Force, F = 5N Change, 9 = 6×10 6 c Formula used, E = F/8 Now, E = F 5. 6×106 05 E = 8.33×105 N/C Hence, the required electric field ins 8.33× 105 N/C
2.7 Required, magnitude of charge, 9=? Given, Electric field, E = 3.4 N/C Formula used, distance, Bulting the value. E = r = 4760 42 3.4 = 9x10° x $ (25×102)2 9x109x9 625 x 104 or 3.4 = 3) ♡ = 3.4×625×154 25×102 т = 9x10³ Nrt/c² 47160 9x109 18 = 2.36 × 10" C Hence, the magnitude of charge is 2.36×10 с
Transcribed Image Text:2.7 Required, magnitude of charge, 9=? Given, Electric field, E = 3.4 N/C Formula used, distance, Bulting the value. E = r = 4760 42 3.4 = 9x10° x $ (25×102)2 9x109x9 625 x 104 or 3.4 = 3) ♡ = 3.4×625×154 25×102 т = 9x10³ Nrt/c² 47160 9x109 18 = 2.36 × 10" C Hence, the magnitude of charge is 2.36×10 с
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